Chapter 24: Problem 64
In 2004 , about 48 million tons of sulfuric acid was produced in the United States. Calculate the amount of sulfur (in grams and moles) used to produce that amount of sulfuric acid.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Formula
Understanding chemical formulas is crucial because they provide important information about the composition and proportion of elements in compounds.
In sulfuric acid, the formula indicates that there's one sulfur atom per molecule, which becomes important when calculating the mass or moles of sulfur needed for manufacturing a certain quantity of sulfuric acid.
Molar Mass
For sulfuric acid \( H_2SO_4 \), the molar mass can be calculated by:
- Hydrogen: \( 2 \times 1 = 2 \) g/mol
- Sulfur: \( 1 \times 32 = 32 \) g/mol
- Oxygen: \( 4 \times 16 = 64 \) g/mol
This means that one mole of sulfuric acid weighs 98 grams. Knowing the molar mass allows us to convert between the mass of a substance and the amount in moles, facilitating chemical calculations.
Conversion of Units
Since 1 ton is equivalent to 1,000,000 grams, calculating the total mass in grams for 48 million tons involves multiplication:
- 48 million tons \( = 48,000,000 \times 1,000,000 \) grams = \( 48 \times 10^{12} \) grams.
Stoichiometry
To determine the amount of sulfur needed for sulfuric acid production, we use stoichiometry. Since the chemical formula \( H_2SO_4 \) indicates one sulfur per molecule, the moles of sulfur will equal the moles of sulfuric acid. First, we calculate the moles of sulfuric acid using its molar mass:
- \( \text{moles of } H_2SO_4 = \frac{48 \times 10^{12} \text{ grams}}{98 \text{ g/mol}} \approx 4.90 \times 10^{11} \text{ moles} \)
To find the mass of sulfur, multiply the moles by the atomic mass of sulfur (32 g/mol):
- \( 4.90 \times 10^{11} \times 32 \approx 1.57 \times 10^{13} \text{ grams of sulfur} \).