Chapter 24: Problem 46
Sodium amide \(\left(\mathrm{NaNH}_{2}\right)\) reacts with water to produce sodium hydroxide and ammonia. Describe this reaction as a Brønsted acid-base reaction.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sodium Amide
In this context, the amide ion acts as a Brønsted base during its reaction with water. It seizes a proton from the water molecule, indicating its fundamental property as a strong base which emerges when it accepts a proton. This capacity to accept a proton highlights the amide ion's role within sodium amide as a critical player in Brønsted acid-base reactions.
Proton Transfer
The step-by-step change involves water, a Brønsted acid, donating a proton. Water loses a proton and becomes a hydroxide ion \(\text{OH}^-\). On the flip side, the amide ion, \(\text{NH}_2^-\), transforms into ammonia, \(\text{NH}_3\), by accepting that proton. This transfer showcases the unique interchange: one molecule acts as a proton donor while the other acts as an acceptor, fulfilling the basic requirement of a Brønsted acid-base reaction.
Hydroxide Ion
In the resulting solution, the hydroxide ion pairs with sodium ions from sodium amide, leading to the creation of sodium hydroxide. The presence of hydroxide ions in the solution indicates basicity, meaning that the solution has a potential to neutralize acids. This basic nature of hydroxide ions often gives rise to their utility in numerous chemical reactions and industrial processes.
Sodium Hydroxide
It highlights the transformation due to the transfer of protons; where initially, sodium amide reacts with water, leads to the formation of sodium hydroxide and ammonia. This reaction exemplifies key aspects of Brønsted acid-base chemistry, where one substance acts as a proton donor and the other as a proton acceptor, finalizing in the creation of two distinctive compounds.