Chapter 24: Problem 25
Draw a Lewis structure for the \(\mathrm{C}_{2}^{2-}\) ion.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Valence Electrons
- Valence electrons determine an element's reactivity and the types of bonds it can form.
- In the \( \mathrm{C}_2^{2-} \) ion, each carbon atom contributes 4 electrons, giving a base total of 8.
- The 2- charge indicates an additional two electrons, resulting in a total of 10 valence electrons to be considered when drawing the Lewis structure.
Octet Rule
- For carbon, attaining an octet means having four covalent bonds, filled with shared electrons.
- In the context of \( \mathrm{C}_2^{2-} \), this rule necessitates ensuring that each carbon atom ends up with 8 electrons shared around it.
Formal Charge
- In the \( \mathrm{C}_2^{2-} \) ion, each carbon atom shares 8 electrons through a triple bond, without extra lone pairs.
- The calculation would show that if the electrons in the bonds are evenly shared, the atoms maintain a formal charge of zero.
- A formal charge of zero is preferred as it often correlates with more stable molecular configurations.
Triple Bond
- For the \( \mathrm{C}_2^{2-} \) ion, the triple bond between the carbon atoms is crucial in distributing all 10 valence electrons effectively.
- This arrangement helps achieve the necessary octet for both atoms, as each carbon effectively shares 6 electrons in the bonding pairs.