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Give an example of hydrogen as (a) an oxidizing agent and \((b)\) a reducing agent.

Short Answer

Expert verified
Hydrogen acts as an oxidizing agent in \( Mg + H_2 \rightarrow MgH_2 \) and a reducing agent in \( CuO + H_2 \rightarrow Cu + H_2O \).

Step by step solution

01

Understanding Oxidizing and Reducing Agents

An oxidizing agent is a substance that gains electrons during a chemical reaction, thereby oxidizing another substance. A reducing agent, on the other hand, gives away electrons to a substance, reducing it.
02

Example for Hydrogen as an Oxidizing Agent

To illustrate hydrogen acting as an oxidizing agent, consider the reaction between hydrogen gas (\( H_2 \)) and magnesium (\( Mg \)). In this reaction, hydrogen gains electrons from magnesium, which means it is reduced and thus acts as the oxidizing agent:\[ Mg + H_2 \rightarrow MgH_2 \]Here, \( H_2 \) is reduced to \( MgH_2 \).
03

Example for Hydrogen as a Reducing Agent

For hydrogen acting as a reducing agent, consider the reaction between copper(II) oxide (\( CuO \)) and hydrogen gas (\( H_2 \)). Here, hydrogen donates electrons to the copper oxide, reducing it to copper while itself being oxidized to water:\[ CuO + H_2 \rightarrow Cu + H_2O \]In this case, \( H_2 \) is oxidized to \( H_2O \) and acts as the reducing agent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen as Oxidizing Agent
Hydrogen can sometimes play the role of an oxidizing agent in chemical reactions. An oxidizing agent is a substance that accepts electrons from other substances. This means it causes another substance to lose electrons, which is known as oxidation.

In certain reactions, hydrogen accepts electrons, demonstrating its role as an oxidizing agent. Consider the interaction with magnesium. When hydrogen gas (\( H_2 \)) reacts with magnesium (\( Mg \)), the hydrogen molecules gain electrons. This reaction can be expressed as:
  • \( Mg + H_2 \rightarrow MgH_2 \)
The magnesium atoms lose electrons while hydrogen atoms gain them, forming magnesium hydride. In this case, hydrogen acts as the oxidizing agent by accepting electrons and reducing itself.
Hydrogen as Reducing Agent
In many chemical reactions, hydrogen acts as a reducing agent. A reducing agent does the opposite of an oxidizing agent. It donates electrons to other substances, causing them to be reduced. This process also results in the oxidizing of hydrogen itself.

A classic example is the reaction between hydrogen gas (\( H_2 \)) and copper(II) oxide (\( CuO \)). In this reaction, hydrogen donates electrons to copper oxide, resulting in the formation of copper metal and water. This reaction is represented as:
  • \( CuO + H_2 \rightarrow Cu + H_2O \)
Here, the hydrogen's electron donation reduces copper oxide to copper, while hydrogen is oxidized to water, showing its role as a reducing agent.
Chemical Reactions Involving Hydrogen
Hydrogen plays versatile roles in chemical reactions, often acting either as an oxidizing agent or a reducing agent, depending on the reaction partners. These reactions are crucial because they illustrate how hydrogen can change the oxidation state of other elements, which is fundamental in chemistry.

Understanding these interactions involves knowing:
  • An oxidizing agent is reduced as it takes electrons.
  • A reducing agent is oxidized as it donates electrons.
This behavior of hydrogen is exploited in various industrial and laboratory settings, including reactions that
  • produce energy,
  • refine metals,
  • and manufacture key chemicals like ammonia.
Grasping these concepts helps us appreciate the significance of hydrogen in catalyzing important chemical processes.

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Most popular questions from this chapter

(a) Which of the following compounds has the greatest ionic character: \(\mathrm{PCl}_{5}, \mathrm{SiCl}_{4}, \mathrm{CCl}_{4}, \mathrm{BCl}_{3} ?(\mathrm{~b})\) Which of the following ions has the smallest ionic radius: \(\mathrm{F}^{-}, \mathrm{C}^{4-}, \mathrm{N}^{3-}, \mathrm{O}^{2-} ?(\mathrm{c})\) Which of the following atoms has the highest ionization energy: \(\mathrm{F}, \mathrm{Cl}, \mathrm{Br}, \mathrm{I} ?\) (d) Which of the following oxides is most acidic: \(\mathrm{H}_{2} \mathrm{O}, \mathrm{SiO}_{2}, \mathrm{CO}_{2} ?\)

Show that chlorine, bromine, and iodine are very much alike by giving an account of their behavior (a) with hydrogen, (b) in producing silver salts, (c) as oxidizing agents, and (d) with sodium hydroxide. (e) In what respects is fluorine not a typical halogen element?

Aqueous copper(II) sulfate solution is blue. When aqueous potassium fluoride is added to the \(\mathrm{CuSO}_{4}\) solution, a green precipitate is formed. If aqueous potassium chloride is added instead, a bright-green solution is formed. Explain what happens in each case.

Metal chlorides can be prepared in a number of ways: (a) direct combination of metal and molecular chlorine, (b) reaction between metal and hydrochloric acid, (c) acid-base neutralization, (d) metal carbonate treated with hydrochloric acid, (e) precipitation reaction. Give an example for each type of preparation.

Both \(\mathrm{N}_{2} \mathrm{O}\) and \(\mathrm{O}_{2}\) support combustion. Suggest one physical and one chemical test to distinguish between the two gases.

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