Chapter 23: Problem 57
Explain the change in bonding when \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) dissociates to form \(\mathrm{AlCl}_{3}\) in the gas phase.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Aluminium Chloride
- At room temperature, aluminium chloride can exist as a dimer \( \mathrm{Al}_{2}\mathrm{Cl}_{6} \).
- These dimers are created when two \( \mathrm{AlCl}_{3} \) units join together.
- It's widely used in various chemical reactions like Friedel-Crafts reactions due to its role as a Lewis acid.
Dimer Dissociation
- In \( \mathrm{Al}_{2}\mathrm{Cl}_{6} \), coordinate covalent bonds stabilize the dimer structure.
- Upon heating, these bonds break, leading the compound to dissociate.
- This results in two separate \( \mathrm{AlCl}_{3} \) molecules in the gas phase.
Coordinate Covalent Bond
- In \( \mathrm{Al}_{2}\mathrm{Cl}_{6} \), coordinate covalent bonds help link two \( \mathrm{AlCl}_{3} \) units together.
- The aluminium atom in one \( \mathrm{AlCl}_{3} \) unit donates a pair of electrons to form a bond with the chloride from another unit.
- Such bonds are crucial for the stability of dimeric structures.
Covalent Bond
- In \( \mathrm{AlCl}_{3} \), each aluminium atom forms three covalent bonds with three chlorine atoms.
- Each bond involves sharing one electron from aluminium and one from chlorine, creating a stable electronic arrangement.
- Covalent bonds are essential for forming stable molecules in most organic and inorganic compounds.