Chapter 23: Problem 55
The pressure of gaseous \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) increases more rapidly with temperature than predicted by the ideal gas equation even though \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) behaves like an ideal gas. Explain.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pressure and Temperature Relationship
This equation means that if the number of moles and the volume remain constant, pressure is directly proportional to temperature. So, as the temperature increases, pressure should increase proportionally—according to the simple direct relationship.
- Larger temperature increases lead to larger pressure increases.
- This scenario assumes no change in molecular structure or intermolecular forces.
However, real gases may deviate from this straightforward relationship due to various factors, one being molecular dissociation, affecting the relationship significantly.
Dissociation of Gases
This process adds more particles to the system.
- Initially: One molecule of \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\).
- After dissociation: Two molecules of \(\mathrm{AlCl}_3\).
Chemical Behavior of Gases
This influence stems from both physical and chemical properties. A gas like \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\), which undergoes dissociation, demonstrates this concept by behaving differently under changing thermal conditions.
- Compared to gases that do not undergo such reactions, dissociative gases change their composition at higher temperatures.
- The splitting increases the gas's ability to expand and its pressure's responsiveness to temperature increases.
Understanding these behaviors is crucial for accurately predicting gas behavior in practical scenarios. This insight points out why some gases deviate from the ideal gas law under certain conditions while maintaining the assumption of ideality in molecular interactions.