Chapter 20: Problem 88
The half-life of \({ }^{27} \mathrm{Mg}\) is \(9.50 \mathrm{~min} .\) (a) Initially there were \(4.20 \times 10^{1227} \mathrm{Mg}\) nuclei present. How many \({ }^{27} \mathrm{Mg}\) nuclei are left 30.0 min later? (b) Calculate the \({ }^{27} \mathrm{Mg}\) activities (in Ci) at \(t=0\) and \(t=30.0\) min. (c) What is the probability that any one \({ }^{27} \mathrm{Mg}\) nucleus decays during a 1 -s interval? What assumption is made in this calculation?
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