Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Outline the principle for dating materials using radioactive isotopes.

Short Answer

Expert verified
Dating materials with isotopes involves measuring decay and applying half-life to calculate age.

Step by step solution

01

Understanding Radioactive Decay

Radioactive isotopes are unstable and decay at a consistent rate over time. This process involves an isotope converting into a stable element at a rate defined by its half-life, which is the time it takes for half of the original isotopic material to decay.
02

The Concept of Half-Life

The half-life of a radioactive isotope is a crucial factor in dating materials. Knowing the half-life allows scientists to calculate how long it has been since a sample started to decay by measuring the ratio of the original isotope to its decay products.
03

Measuring Isotope Ratios

To date a material, scientists measure the present amount of the radioactive isotope and its decay products in the sample. By understanding the current ratio and the isotope's half-life, they calculate how many half-lives have passed.
04

Calculation and Age Determination

Using the data from isotope measurements and applying the principle of exponential decay (expressed as \(N = N_0 e^{- rac{ ext{t}}{ ext{half-life}}}\), where \(N_0\) is the initial quantity), scientists can calculate the age of the material from how much decay has occurred.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a fundamental process where unstable isotopes undergo transformation to become stable elements. This transformation happens at a consistent rate, enabling us to predict how long the process will take. Radioactive isotopes naturally emit particles or radiation, losing part of their mass to eventually reach stability. This decay rate is unique to each isotope, making it a reliable clock for dating purposes.

This natural clock results from the fact that each isotope has a specific way of decaying, either by emitting alpha or beta particles, or through gamma radiation. These emissions lead to the systematic reduction of the parent isotope, gradually forming a stable daughter element. Understanding these characteristics helps us use different isotopes for various types of dating, like carbon-14 for organic remains.
Half-Life
The concept of half-life is central to understanding radioactive decay and dating materials. A half-life is defined as the time required for half of the original isotope in a sample to decay into its products.

This consistent timing allows scientists to measure the elapsed time since a sample began to decay. For instance, if an isotope has a half-life of 1,000 years, in that time, only 50% of the original isotope will remain. After another 1,000 years, only 25% would be left, and so forth.

Knowing the half-life can tell how many half-lives have passed since the sample formation. This information helps us backtrack to the moment when the isotope began its decay, revealing the age of the material. This is why half-life is essential in the field of geochronology and archaeology.
Isotope Ratios
Isotope ratios are crucial in determining the age of a material using radioactive isotopes. This involves comparing the amount of the original radioactive isotope to its decay products within a sample.

Measurement of these ratios allows scientists to estimate how many times the sample has halved, providing insight into its age. By analyzing these proportions alongside with the known half-life of the isotope, scientists can accurately estimate the number of half-lives that have passed.

For example, if a sample shows an isotope ratio where only one-fourth of the original isotope remains, it indicates that two half-lives have elapsed. These calculations form the backbone of radiometric dating methods, helping scientists date ancient objects and geological samples.
Exponential Decay
Exponential decay is a mathematical concept describing the decline in the quantity of a radioactive isotope over time. The formula used is given by \(N = N_0 e^{-\frac{t}{\text{half-life}}}\), where \(N_0\) represents the initial amount, \(N\) is the remaining amount, and \(t\) is time.

This model helps in predicting how quickly or slowly an isotope decays. It reflects how the amount of isotope decreases at a rate proportional to its current value, creating a smooth declining curve.

This principle allows scientists to use the properties of exponential functions to date materials accurately. By inputting the current ratio of isotopes and their decay products, scientists can calculate the elapsed time since the material started to decay, thus determining its age.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following redox reaction: \(\mathrm{IO}_{4}^{-}(a q)+2 \mathrm{I}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) \(\mathrm{I}_{2}(s)+\mathrm{IO}_{3}^{-}(a q)+2 \mathrm{OH}^{-}(a q)\) When \(\mathrm{KIO}_{4}\) is added to a solution containing iodide ions labeled with radioactive iodine-128, all the radioactivity appears in \(\mathrm{I}_{2}\) and none in the \(\mathrm{IO}_{3}^{-}\) ion. What can you deduce about the mechanism for the redox process?

Nuclei with an even number of protons and an even number of neutrons are more stable than those with an odd number of protons and/or an odd number of neutrons. What is the significance of the even numbers of protons and neutrons in this case?

Modern designs of atomic bombs contain, in addition to uranium or plutonium, small amounts of tritium and deuterium to boost the power of explosion. What is the role of tritium and deuterium in these bombs?

In \(2006,\) an ex-KGB agent was murdered in London. The investigation following the agent's death revealed that he was poisoned with the radioactive isotope \({ }^{210} \mathrm{Po}\) which had apparently been added to his food. (a) \({ }^{210} \mathrm{Po}\) is prepared by bombarding \({ }^{209} \mathrm{Bi}\) with neutrons. Write an equation for the reaction. (b) The half-life of \({ }^{210} \mathrm{Po}\) is 138 days. It decays by \(\alpha\) particle emission. Write the equation for the decay process. (c) Calculate the energy of an emitted \(\alpha\) particle. Assume both the parent and daughter nuclei have zero kinetic energy. The atomic masses of \({ }^{210} \mathrm{Po},{ }^{206} \mathrm{~Pb},\) and \({ }_{2}^{4} \alpha\) are 209.98286 \(205.97444,\) and 4.00150 amu, respectively. (d) Ingestion of \(1 \mu \mathrm{g}\) of \({ }^{210}\) Po could prove fatal. What is the total energy released by this quantity of \({ }^{210}\) Po over the course of 138 days?

The quantity of a radioactive material is often measured by its activity (measured in curies or millicuries) rather than by its mass. In a brain scan procedure, a \(70-\mathrm{kg}\) patient is injected with \(20.0 \mathrm{mCi}\) of \({ }^{99 \mathrm{~m}} \mathrm{Tc},\) which decays by emitting \(\gamma\) -ray photons with a half-life of \(6.0 \mathrm{~h}\). Given that the \(\mathrm{RBE}\) of these photons is 0.98 and only two-thirds of the photons are absorbed by the body, calculate the rem dose received by the patient. Assume all the \({ }^{99 \mathrm{~m}}\) Tc nuclei decay while in the body. The energy of a \(\gamma\) -ray photon is \(2.29 \times 10^{-14} \mathrm{~J}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free