Chapter 2: Problem 63
Write the formulas for the following compounds: (a) rubidium nitrite, (b) potassium sulfide, (c) sodium hydrogen sulfide, (d) magnesium phosphate, (e) calcium hydrogen phosphate, (f) lead(II) carbonate, (g) tin(II) fluoride, (h) ammonium sulfate, (i) silver perchlorate, (j) boron trichloride.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Compounds
- Examples include sodium chloride ( ext{Na}^+ ext{Cl}^-), magnesium oxide ( ext{Mg}^{2+} ext{O}^{2-}), and calcium carbonate ( ext{Ca}^{2+} ext{CO}_3^{2-}).
- The forces holding these ions together are strong electrostatic forces called ionic bonds.
- Properties of these compounds include high melting and boiling points due to the strong bonds.
Cations and Anions
- For example, sodium ( ext{Na}^+) loses one electron to become a cation, and magnesium ( ext{Mg}^{2+}) loses two electrons.
- For example, chloride ( ext{Cl}^-) gains one electron, and sulfide ( ext{S}^{2-}) gains two electrons.
Polyatomic Ions
- Common polyatomic ions include nitrate ( ext{NO}_3^-), sulfate ( ext{SO}_4^{2-}), and phosphate ( ext{PO}_4^{3-}).
- Ammonium ( ext{NH}_4^+) is a frequently encountered polyatomic cation.
- Formulas can include parentheses to denote the number of polyatomic ions as needed, like in ammonium sulfate ext{(NH}_4)_2 ext{SO}_4.
Charge Balancing
- If calcium ( ext{Ca}^{2+}) combines with phosphate ( ext{PO}_4^{3-}), we need three calcium ions for every two phosphate ions to balance the charge, leading to the formula ext{Ca}_3( ext{PO}_4)_2.
- In the case of creating potassium sulfide, two potassium ions ( ext{K}^+) are required to balance one sulfide ion ( ext{S}^{2-}), resulting in ext{K}_2 ext{S}.
- Understanding the valency and common charges of ions aids in predicting how many of each ion will be needed.