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Explain why most useful galvanic cells give voltages of no more than 1.5 to \(2.5 \mathrm{~V}\). What are the prospects for developing practical galvanic cells with voltages of \(5 \mathrm{~V}\) or more?

Short Answer

Expert verified
Useful galvanic cells have voltages of 1.5-2.5 V due to material and reaction limitations. Achieving 5 V with single cells is challenging; series of cells can be used instead.

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01

Understanding Maximum Voltage

In a galvanic cell, the voltage is determined by the difference in electrode potentials between the anode and cathode. This potential difference generally results in voltages between 1.5 and 2.5 V, as most common redox reactions with accessible materials offer electrode potentials within this range.
02

Chemical and Material Limitations

To achieve a potential difference significantly higher than 2.5 V, one would need redox reactions with either very high or very low electrode potentials. However, finding suitable materials that can stably exist and react without decomposing or causing unwanted side reactions is challenging.
03

Voltage and Safety Concerns

Beyond approximately 2.5 V, the energy density increases, leading to potentially more vigorous reactions. This makes managing overheating and ensuring the stability of materials even more difficult, leading to significant safety concerns.
04

Prospects for Higher Voltage Cells

While achieving voltages above 3 V is difficult with single cells, stacking cells in series is a common approach to reach higher voltages like 5 V or more in practical applications. Continuous research in materials science might eventually lead to more stable high potential redox reactions, but until then, stacks of cells are the primary method.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrode Potentials
In galvanic cells, the electrode potentials are the driving force behind voltage generation. This refers to the potential difference between the anode and cathode materials. The potential difference is what enables the flow of electrons from one electrode to another. Most common redox reactions involve materials with electrode potentials that fall between 1.5 to 2.5 V. This is because materials with suitable stability and reactivity usually exhibit potentials within this range.
To achieve higher voltages, reactions must involve materials with extreme electrode potentials. However, finding materials that can safely and effectively maintain these potentials without degrading or causing side reactions is complicated. The challenge lies in the delicate balance between achieving a high potential while ensuring material stability.
Generally, the potential difference in a galvanic cell must remain within a safe range to prevent decomposition or material failure. Thus, the typical voltage range for most practical galvanic cells remains between 1.5 to 2.5 V.
Redox Reactions
Redox reactions form the core of galvanic cells, driving the conversion of chemical energy into electrical energy. These reactions involve the transfer of electrons between chemical species. The key processes in a redox reaction are oxidation, which is the loss of electrons, and reduction, which is the gain of electrons.
For a galvanic cell to work effectively, it must have a redox pair consisting of a good reducing agent and an excellent oxidizing agent.
  • The reducing agent donates electrons, undergoing oxidation.
  • The oxidizing agent accepts electrons, undergoing reduction.
In theory, higher potential differences could be achieved by choosing redox reactions with stronger oxidizing and reducing agents. However, material limitations often make it difficult to find suitable reactants that are stable and efficient under practical conditions without undesirable side effects. This limits the types of redox reactions that can be used in everyday galvanic cells.
Energy Density
Energy density is a crucial parameter in evaluating the effectiveness of galvanic cells. It reflects how much energy a cell can store and supply compared to its size. High energy density means that a battery can supply a large amount of energy without being too large.
When potentials exceed about 2.5 V, the energy density escalates, making the reactions more energetic and challenging to control. Managing increased energy density involves careful thermal regulation and advancements in material stability to avoid overheating or explosive outcomes.
In single galvanic cells, the highest voltages typically remain below 3 V due to the trade-off between energy density and safety. For applications requiring higher voltages, cells are often stacked in series, combining the potentials of individual cells to reach desired voltage outputs without exceeding safe operational limits.
Materials Science
Materials science is at the forefront of developing advanced galvanic cells. It involves the study of materials and their properties to create new and improved substances that can handle higher potentials safely. The focus is on achieving stability under extreme conditions.
Researchers explore new electrode materials that offer higher voltage potentials without compromising on safety. This includes testing novel compounds and alloys that may provide better electrochemical performance.
Continuous advancements in this field could lead to more durable, high-performance materials capable of reaching and maintaining voltages exceeding current standards. However, until these breakthroughs are achieved, strategies like connecting multiple cells in series remain the mainstay for achieving higher voltage outputs in practical applications.

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Most popular questions from this chapter

Given that: $$ \begin{array}{ll} 2 \mathrm{Hg}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Hg}_{2}^{2+}(a q) & E^{\circ}=0.92 \mathrm{~V} \\\ \mathrm{Hg}_{2}^{2+}(a q)+2 e^{-} \longrightarrow 2 \mathrm{Hg}(l) & E^{\circ}=0.85 \mathrm{~V} \end{array} $$ calculate \(\Delta G^{\circ}\) and \(K\) for the following process at \(25^{\circ} \mathrm{C}:\) $$\mathrm{Hg}_{2}^{2+}(a q) \longrightarrow \mathrm{Hg}^{2+}(a q)+\mathrm{Hg}(l)$$ (The preceding reaction is an example of a disproportionation reaction in which an element in one oxidation state is both oxidized and reduced.)

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