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For a number of years, it was not clear whether mercury(I) ions existed in solution as \(\mathrm{Hg}^{+}\) or as \(\mathrm{Hg}_{2}^{2+}\). To distinguish between these two possibilities, we could set up the following system: $$ \operatorname{Hg}(l) \mid \text { soln } \mathrm{A} \| \operatorname{soln} \mathrm{B} \mid \operatorname{Hg}(l)$$ where soln A contained 0.263 g mercury(I) nitrate per liter and soln B contained \(2.63 \mathrm{~g}\) mercury(I) nitrate per liter. If the measured emf of such a cell is \(0.0289 \mathrm{~V}\) at \(18^{\circ} \mathrm{C},\) what can you deduce about the nature of the mercury(I) ions?

Short Answer

Expert verified
Mercury(I) ions exist as \( \mathrm{Hg}_{2}^{2+} \) in solution.

Step by step solution

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01

Understand the System

This electrochemical cell is set up with solutions containing mercury(I) nitrate at different concentrations. We need to determine if mercury exists in the solution as \( \mathrm{Hg}^{+} \) or \( \mathrm{Hg}_{2}^{2+} \). We use the given EMF to make this determination.
02

Identify Nernst Equation for the Situation

The Nernst equation relates the cell potential to the concentration of ions: \[ E = E^0 - \frac{RT}{nF} \ln Q \]Where \(E\) is the cell potential, \(E^0\) is the standard cell potential, \(R\) is the gas constant, \(T\) is the temperature in Kelvin, \(n\) is the number of moles of electrons transferred in the reaction, \(F\) is Faraday's constant, and \(Q\) is the reaction quotient.
03

Calculate Reaction Quotient (Q)

For mercury(I) in solution as \( \mathrm{Hg}_{2}^{2+} \), the potential difference would be due to the concentration difference. First, calculate the molarity of \( \mathrm{Hg}_{2}^{2+} \) for solution A and B from their given mass concentrations.
04

Calculate Molarity from Mass

Molar mass of \( \mathrm{Hg}_{2} \mathrm{(NO_3)_2} \) is approximately 525.2 g/mol. Molarity for solution A is \( \frac{0.263 \text{ g/L}}{525.2 \text{ g/mol}} \approx 0.0005 \text{ mol/L} \). Similar calculation for solution B gives \( \frac{2.63 \text{ g/L}}{525.2 \text{ g/mol}} \approx 0.005 \text{ mol/L} \).
05

Calculate the EMF using the Nernst Equation

Assume the reaction is \( \mathrm{Hg}_{2}^{2+}(aq) + 2e^- \leftrightarrow 2 \mathrm{Hg}(l) \),with \( n = 2 \). Calculate \( Q = \frac{[\mathrm{Hg}_{2}^{2+}(A)]}{[\mathrm{Hg}_{2}^{2+}(B)]} \). Substitute these values into Nernst equation:\[ 0.0289 = 0 - \frac{RT}{2F} \ln \left( \frac{0.0005}{0.005} \right) \]
06

Solve the Nernst Equation for Confirmation

Convert temperature: \( T = 18^{\circ} \mathrm{C} = 291 \text{ K} \). Using \[ R = 8.314 \text{ J/(mol K)}, F = 96500 \text{ C/mol} \], we get:\[ 0.0289 \text{ V} = - \frac{8.314 \times 291}{2 \times 96500} \ln(0.1) \]. This gives an approximate match, supporting the reaction involving \( \mathrm{Hg}_{2}^{2+} \).
07

Conclusion

Given that the calculations using \( \mathrm{Hg}_{2}^{2+} \) provide a reasonable match with the experimental EMF, we conclude that mercury(I) ions exist as \( \mathrm{Hg}_{2}^{2+} \) in solution, and not as \( \mathrm{Hg}^{+} \).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrochemical Cell
An electrochemical cell is a device that can generate electrical energy from chemical reactions or facilitate chemical reactions through the introduction of electrical energy. Within this setup, two half-cells are connected by a salt bridge or a porous separator, allowing ions to flow between them to maintain electrical neutrality.

The system in our case study involves mercury and mercury(I) nitrate solutions at different concentrations. By measuring the electromotive force (emf) or potential difference between these two solutions, we gain insights about the species present in the solutions, specifically mercury(I) ions. Here, the cell design helps us differentiate whether mercury(I) exists as solitary ions (\( \mathrm{Hg}^{+} \)) or in a dimer form (\( \mathrm{Hg}_{2}^{2+} \)).
  • One half-cell contains a more concentrated solution of mercury(I) nitrate, while the other has a less concentrated solution.
  • The electrode potential difference is due to the concentration gradient of the mercury(I) ions.
This type of measurement is typical in solving questions about oxidation states and molecular structures in solution.
Mercury(I) Ions
Mercury(I) ions have sparked interest due to their uncommon charge and bonding configuration. Often, there is confusion about their form in solution, begging the question of whether they exist as monomeric ions \( \mathrm{Hg}^{+} \) or as dimers \( \mathrm{Hg}_{2}^{2+} \). In the latter form, two mercury atoms share electrons, forming a diatomic cation.

The structure \( \mathrm{Hg}_{2}^{2+} \) is stabilized by a pair bond between the two mercury atoms. This results in a reduction in overall energy, making it a more common form in mercury(I) compounds. Experimental setups, such as the electrochemical cell described, help in confirming the molecular identity.
  • Dimer form: \( \mathrm{Hg}_{2}^{2+} \)
    - More stable
  • Monomer form: \( \mathrm{Hg}^{+} \)
    - Less common due to instability
This concept is crucial in understanding how mercury behaves in various chemical and environmental situations.
Reaction Quotient
The reaction quotient, often denoted as \( Q \), is a quantitative measure that reflects the relative concentrations of reactants and products involved in a chemical reaction at any given moment. It helps predict the direction in which the reaction will proceed to reach equilibrium.

In the case of differing mercury(I) nitrate concentrations between two solutions, the reaction quotient is derived from these concentrations. For the assumed dimeric presence of \( \mathrm{Hg}_{2}^{2+} \):
\[ Q = \frac{[\mathrm{Hg}_{2}^{2+} (\text{solution A})]}{[\mathrm{Hg}_{2}^{2+} (\text{solution B})]} \]
The value of \( Q \) changes based on concentration differences, influencing the cell potential as described by the Nernst Equation. When calculations match observed potentials, it confirms the stoichiometry of the ions involved.
  • The closer \( Q \) is to the equilibrium constant \( K \), the closer the reaction is to equilibrium.
  • Dramatic changes in \( Q \) can induce shifts in the reaction direction.
This makes \( Q \) essential for calculations in electrochemical cells and understanding chemical dynamics.
Standard Cell Potential
The standard cell potential \( E^0 \) is a crucial concept in electrochemistry, representing the maximum voltage difference between two half-cells when concentrations of all species are at their standard states (usually 1 M concentration, 1 atm pressure, and 25°C temperature). It is the reference point for potentials in the Nernst equation that describe non-standard conditions.

In the provided electrochemical cell description, although no specific \( E^0 \) was given for \( \mathrm{Hg}_{2}^{2+} \), it serves as a benchmark.
The measurement of \( 0.0289 \, \mathrm{V} \) relates to how far the system diverges from standard state potentials:
\[ E = E^0 - \frac{RT}{nF} \ln Q \]
Even a small emf can testify to significant concentration discrepancies. By comparing experimental potential changes to theoretical predictions, conclusions about molecular arrangements can be drawn, such as deducing that \( \mathrm{Hg}_{2}^{2+} \) is the prevalent form in the solution.
  • \( E^0 \) values provide comparative insights between different ionic species.
  • A positive \( E^0 \) indicates a spontaneous reaction under standard conditions.
This concept allows chemists to predict behavior and reaction trends in more complex systems.

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Most popular questions from this chapter

Describe the basic features of a galvanic cell. Why are the two components of the cell separated from each other?

As discussed in Section \(19.5,\) the potential of \(\mathrm{a}\) concentration cell diminishes as the cell operates and the concentrations in the two compartments approach each other. When the concentrations in both compartments are the same, the cell ceases to operate. At this stage, is it possible to generate a cell potential by adjusting a parameter other than concentration? Explain.

Balance the following redox equations by the halfreaction method: (a) \(\mathrm{H}_{2} \mathrm{O}_{2}+\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{H}_{2} \mathrm{O}\) (in acidic solution) (b) \(\mathrm{Cu}+\mathrm{HNO}_{3} \longrightarrow \mathrm{Cu}^{2+}+\mathrm{NO}+\mathrm{H}_{2} \mathrm{O}\) (in acidic solution) (c) \(\mathrm{CN}^{-}+\mathrm{MnO}_{4}^{-} \longrightarrow \mathrm{CNO}^{-}+\mathrm{MnO}_{2}\) (in basic solution) (d) \(\mathrm{Br}_{2} \longrightarrow \mathrm{BrO}_{3}^{-}+\mathrm{Br}^{-}\) (in basic solution) (e) \(\mathrm{S}_{2} \mathrm{O}_{3}^{2-}+\mathrm{I}_{2} \longrightarrow \mathrm{I}^{-}+\mathrm{S}_{4} \mathrm{O}_{6}^{2-}\) (in acidic solution)

Given that: $$ \begin{array}{ll} 2 \mathrm{Hg}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Hg}_{2}^{2+}(a q) & E^{\circ}=0.92 \mathrm{~V} \\\ \mathrm{Hg}_{2}^{2+}(a q)+2 e^{-} \longrightarrow 2 \mathrm{Hg}(l) & E^{\circ}=0.85 \mathrm{~V} \end{array} $$ calculate \(\Delta G^{\circ}\) and \(K\) for the following process at \(25^{\circ} \mathrm{C}:\) $$\mathrm{Hg}_{2}^{2+}(a q) \longrightarrow \mathrm{Hg}^{2+}(a q)+\mathrm{Hg}(l)$$ (The preceding reaction is an example of a disproportionation reaction in which an element in one oxidation state is both oxidized and reduced.)

A piece of magnesium ribbon and a copper wire are partially immersed in a \(0.1 M \mathrm{HCl}\) solution in a beaker. The metals are joined externally by another piece of metal wire. Bubbles are seen to evolve at both the \(\mathrm{Mg}\) and Cu surfaces. (a) Write equations representing the reactions occurring at the metals. (b) What visual evidence would you seek to show that Cu is not oxidized to \(\mathrm{Cu}^{2+} ?(\mathrm{c})\) At some stage, \(\mathrm{NaOH}\) solution is added to the beaker to neutralize the HCl acid. Upon further addition of \(\mathrm{NaOH},\) a white precipitate forms. What is it?

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