Chapter 19: Problem 61
Tarnished silver contains \(\mathrm{Ag}_{2} \mathrm{~S} .\) The tarnish can be removed by placing silverware in an aluminum pan containing an inert electrolyte solution, such as \(\mathrm{NaCl}\). Explain the electrochemical principle for this procedure. [The standard reduction potential for the half- cell reaction \(\mathrm{Ag}_{2} \mathrm{~S}(s)+2 e^{-} \longrightarrow 2 \mathrm{Ag}(s)+\mathrm{S}^{2-}(a q)\) is \(\left.-0.71 \mathrm{~V} .\right]\)
Short Answer
Step by step solution
Understanding the Problem
Identify the Reactions
Calculate Cell Potential
Write the Overall Reaction
Explain the Electrochemical Principle
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Redox Reactions
- Reduction involves the gain of electrons, converting tarnished silver back to bright silver metal.
- Oxidation involves the loss of electrons, as aluminum changes to aluminum ions.
Cell Potential
In the case of tarnish removal, the cell potential formula used is:
- \[ E_{ ext{cell}} = E^{0}_{ ext{cathode}} - E^{0}_{ ext{anode}} \]
This spontaneous reaction is what makes using the aluminum pan effective in removing the tarnish without the need for extra energy.
Standard Reduction Potential
Each half-reaction in a redox process has its own standard reduction potential, measured under standard conditions (all concentrations at 1 mol/L, gases at 1 atm, and a specified temperature, usually 25°C). In our example:
- The silver sulfide reaction has a standard reduction potential of \(-0.71 \) volts.
- The aluminum reaction has a more negative standard reduction potential of \(-1.66 \) volts.
Knowing these potentials helps in designing electrochemical cells that harness the reactivity of different materials.
Galvanic Cells
In the case of tarnished silverware, the arrangement can be thought of as a galvanic cell with aluminum acting as the anode (site of oxidation) and silver sulfide serving as the cathode (site of reduction). The process includes:
- The anode, where aluminum undergoes oxidation, losing electrons.
- The cathode, where silver ions gain electrons and are reduced back to silver metal.
- The electrolyte, which facilitates the flow of ions without permitting the solutions to mix directly.
Understanding the principles of galvanic cells provides insight into creating effective and practical electrochemical systems.