Chapter 19: Problem 43
The half-reaction at an electrode is: \(\mathrm{Mg}^{2+}(\) molten \()+2 e^{-} \longrightarrow \mathrm{Mg}(s)\) Calculate the number of grams of magnesium that can be produced by supplying \(1.00 \mathrm{~F}\) to the electrode.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Half-Reaction
This equation shows the reduction process, where magnesium ions \( (\mathrm{Mg}^{2+}) \) gain electrons \((2\, e^{-})\) to form solid magnesium \((\mathrm{Mg})\). Understanding the half-reaction is crucial because it helps determine how many electrons are involved and the relationships between ions and the solid produced.
Basics of Electrolysis
The device where electrolysis takes place is called an electrolytic cell. In this cell, the source of electrical energy usually compels ions to move, enabling previously unattainable compound separation or formulation.
Calculating Moles of Electrons
In this exercise, 1.00 Faraday (\( \mathrm{F} \)) of electrical charge supplies exactly 1 mole of electrons. Since the half-reaction \( \mathrm{Mg}^{2+} + 2 e^{-} \rightarrow \mathrm{Mg} \) requires 2 electrons (\(2 e^{-}\)) to convert magnesium ions into magnesium metal, 1.00 Faraday enables the production of 0.5 moles of magnesium.
Understanding Molar Mass of Magnesium
In the context of our problem, using 1.00 Faraday of charge produces 0.5 moles of magnesium. To calculate the mass of magnesium produced, we need to multiply the number of moles by the molar mass: \[ 0.5\, \text{moles} \times 24.3\, \text{g/mol} = 12.15\, \text{g} \].Thus, 12.15 grams of magnesium can be produced, showcasing the importance of understanding the molar mass to find the mass of substances generated in electrolysis.