Chapter 19: Problem 107
Consider a Daniell cell operating under non-standardstate conditions. Suppose that the cell's reaction is multiplied by 2 . What effect does this have on each of the following quantities in the Nernst equation: (a) \(E\) (b) \(E^{\circ},(\mathrm{c}) Q\) (d) \(\ln Q\), (e) \(n\) ?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cell Potential
As described by the Nernst equation, the cell potential under non-standard conditions can vary according to the concentration of reactants and products. It is calculated as:
- \(E = E^{\circ} - \frac{RT}{nF} \ln Q\)
Standard Cell Potential
- It remains constant, regardless of the scaling of the chemical reaction or the stoichiometric coefficients, as it reflects the inherent properties of the reactants under standard conditions.
Reaction Quotient
- In a Daniell cell, \(Q\) is determined by the expression formed from the ratio of the activities (or concentrations) of the products raised to their coefficients, divided by the activities of the reactants raised to theirs.
Daniell Cell
- In the Daniell cell, zinc acts as the anode, oxidizing by losing electrons, and copper acts as the cathode, reducing by gaining those electrons.
- This setup generates an electric current proportional to the standard and actual cell potentials.
Number of Moles of Electrons
- \(E = E^{\circ} - \frac{RT}{nF} \ln Q\),