Chapter 18: Problem 75
Predict whether the entropy change is positive or negative for each of these reactions: (a) \(\mathrm{Zn}(s)+2 \mathrm{HCl}(a q) \rightleftharpoons \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g)\) (b) \(\mathrm{O}(g)+\mathrm{O}(g) \rightleftharpoons \mathrm{O}_{2}(g)\) (c) \(\mathrm{NH}_{4} \mathrm{NO}_{3}(s) \rightleftharpoons \mathrm{N}_{2} \mathrm{O}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(2 \mathrm{H}_{2} \mathrm{O}_{2}(l) \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phase Changes
Consider water turning into steam. This is a phase change from liquid to gas. Here, the molecules gain energy and move more freely, occupying more space and having more possible positions, increasing entropy.
Microstates
For instance, let's take a look at a pack of playing cards. If we just shuffle them, the number of ways we can arrange them is vast. The greater the number of arrangements, the higher the entropy. Similarly, a gas with more dispersed molecules has more microstates than a tightly packed solid, contributing to its higher entropy.
Gaseous State
When a reaction involves the formation of gases from solids or liquids, like the evolution of \(H_2\) gas in a chemical reaction, it typically results in a positive change in entropy. This is because gas molecules occupy a larger volume, allowing for more random arrangements, i.e., more microstates.
- Gases are highly compressible due to the large distances between molecules.
- Each molecule in the gas is independent of others, moving randomly and in various directions.
Solid State
In the reaction where \(NH_4NO_3(s)\) changes into gaseous products like \(N_2O(g)\) and \(H_2O(g)\), the shift from solid to gas greatly increases potential microstates. The structure of solids restricts particle movement, significantly reducing entropy as compared to gases, where particles are free to move.