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Crystallization of sodium acetate from a supersaturated solution occurs spontaneously (see Figure 13.2 ). Based on this, what can you deduce about the signs of \(\Delta S\) and \(\Delta H ?\)

Short Answer

Expert verified
ΔS is negative and ΔH is negative.

Step by step solution

01

Understand the Process

Crystallization involves the formation of a solid crystal structure from a supersaturated solution. In a supersaturated solution, there's more solute (sodium acetate) than the solvent can normally accommodate. When crystallization occurs, the system moves from a higher energy state (disturbed and disordered) to a lower energy state (ordered crystal formation). This is a spontaneous process.
02

Analyze the Entropy Change ( ΔS )

Entropy ( ΔS ) is a measure of the disorder in a system. Since the crystallization process involves going from a disordered solution to an ordered crystal, the entropy decreases. Therefore, ΔS for the process would be negative.
03

Consider the Enthalpy Change ( ΔH )

Enthalpy ( ΔH ) reflects the heat absorbed or released during a process. Since the process is spontaneous even though it decreases entropy, it implies heat is released, which compensates for the decrease in entropy. Thus, ΔH is negative because the process is exothermic.
04

Apply the Gibbs Free Energy Equation

Using the Gibbs free energy equation ΔG = ΔH - TΔS , for a spontaneous process, ΔG must be negative. Given ΔH is negative and ΔS is negative, ΔG will be negative if the magnitude of ΔH is large enough to compensate for the (- TΔS) term.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Supersaturated Solution
A supersaturated solution is like a ticking time bomb of crystals. It has more solute than the solvent can usually dissolve. Imagine trying to fit extra sugar into your tea when it’s already sweet enough. This solution is unstable. It's ready to release the extra solute in the form of crystals. This transformation can happen quickly when triggered, such as by a dust particle or a seed crystal. When sodium acetate crystallizes from this supersaturated state, it moves from chaos towards order. The solute particles leave the solution to form a neat crystal lattice. This process, going from high energy disorder to low energy order, is called crystallization.
Entropy Change
Entropy measures disorder in a system. Think of it like the messiness of your room. The more cluttered it is, the higher the entropy. During crystallization, things get ordered. The messy, mixed solution of sodium acetate becomes a tidy crystal structure. As a result, entropy decreases during this process. Mathematically, the change in entropy \((\Delta S)\) for such a process becomes negative, since the order in the system increases and the disorder decreases.
Enthalpy Change
Enthalpy is about heat exchange during a process. It's like whether your room gets warmer or cooler. The crystallization of sodium acetate releases heat, making the surrounding space warmer. This release of heat occurs because the bonds forming in the crystal release energy. Hence, this is an exothermic process where the change in enthalpy \((\Delta H)\) is negative. The system loses energy, transitioning into a more stable state.
Gibbs Free Energy
Gibbs free energy helps predict the spontaneity of a process. Imagine it as the energetic currency for a process to occur without external help. The equation \(\Delta G = \Delta H - T\Delta S\) pulls together enthalpy, entropy, and temperature to tell us if a process can just happen. For crystallization, we need \(\Delta G\) to be negative for it to be "free." If \(\Delta H\) is negative (energy is released), and \(\Delta S\) is also negative (system gets ordered), the process can still be spontaneous if the energy released is greater than the energy needed to increase order (\(T\Delta S\) term).
Spontaneous Process
A spontaneous process is like a ball rolling down a hill, happening on its own without a push. When the energy balance favors the shift towards order or stability, it happens naturally. In the case of sodium acetate crystallizing, the process occurs spontaneously. Although entropy decreases, the large amount of heat released (negative \(\Delta H\)) more than compensates. Together, these factors ensure a negative Gibbs free energy \(\Delta G\), signaling that the crystallization takes place without external intervention.

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Most popular questions from this chapter

At \(0 \mathrm{~K},\) the entropy of carbon monoxide crystal is not zero but has a value of \(4.2 \mathrm{~J} / \mathrm{K} \cdot \mathrm{mol},\) called the residual entropy. According to the third law of thermodynamics, this means that the crystal does not have a perfect arrangement of the CO molecules. (a) What would be the residual entropy if the arrangement were totally random? (b) Comment on the difference between the result in part (a) and \(4.2 \mathrm{~J} / \mathrm{K} \cdot\) mol. (Hint: Assume that each CO molecule has two choices for orientation, and use Equation 18.1 to calculate the residual entropy.)

Consider the following facts: Water freezes spontaneously at \(-5^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm},\) and ice has a lower entropy than liquid water. Explain how a spontaneous process can lead to a decrease in entropy.

Which of the following is not accompanied by an increase in the entropy of the system: (a) mixing of two gases at the same temperature and pressure, (b) mixing of ethanol and water, (c) discharging a battery, (d) expansion of a gas followed by compression to its original temperature, pressure, and volume?

As an approximation, we can assume that proteins exist either in the native (physiologically functioning) state or the denatured state. The standard molar enthalpy and entropy of the denaturation of a certain protein are \(512 \mathrm{~kJ} / \mathrm{mol}\) and \(1.60 \mathrm{~kJ} / \mathrm{K} \cdot \mathrm{mol}\), respectively. Comment on the signs and magnitudes of these quantities, and calculate the temperature at which the denaturation becomes spontaneous.

The enthalpy change in the denaturation of a certain protein is \(125 \mathrm{~kJ} / \mathrm{mol}\). If the entropy change is \(397 \mathrm{~J} / \mathrm{K} \cdot \mathrm{mol},\) calculate the minimum temperature at which the protein would denature spontaneously.

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