Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Which of the following are not state functions: \(S, H, q, w, T ?\)

Short Answer

Expert verified
Heat (q) and work (w) are not state functions.

Step by step solution

Achieve better grades quicker with Premium

  • Unlimited AI interaction
  • Study offline
  • Say goodbye to ads
  • Export flashcards

Over 22 million students worldwide already upgrade their learning with Vaia!

01

Understanding State Functions

A state function is a property whose value does not depend on the path taken to reach that specific value. In other words, a state function depends only on the initial and final states of a system, not on how the system arrived at that state.
02

List of Properties

The properties given in the exercise include entropy ( S ), enthalpy ( H ), heat ( q ), work ( w ), and temperature ( T ). We need to determine which of these are state functions.
03

Analyzing Entropy (S) and Enthalpy (H)

Both entropy ( S ) and enthalpy ( H ) are state functions because they depend only on the state of the system, not how it was achieved. For any given state of a system, S and H are defined regardless of the processes that led to those states.
04

Analyzing Heat (q) and Work (w)

Heat ( q ) and work ( w ) are not state functions. They are path functions because their values depend on the specific path taken by a system to change states. The amount of heat transferred or work done can vary based on how the change is carried out.
05

Analyzing Temperature (T)

Temperature ( T ) is a state function. Like entropy and enthalpy, the temperature of a system is determined only by its current state, not on the process used to reach that temperature.
06

Conclusion

Based on the analysis, the properties that are not state functions among the given options are heat ( q ) and work ( w ).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Path Functions
In thermodynamics, path functions are properties that depend on the specific path taken to reach a particular state. Unlike state functions, they are not determined solely by the initial and final states. Instead, the quantity of a path function can vary depending on how a change is realized.

Key examples of path functions:
  • Heat (q): The amount of heat transferred depends on the way energy is exchanged between a system and its surroundings. Different paths can lead to different heat values.
  • Work (w): Just like heat, the work done by or on a system is path-dependent. For instance, compressing a gas slowly versus quickly can result in different quantities of work.
Understanding path functions is crucial because it helps in analyzing energy exchanges in engineering and natural processes. These concepts are vital in many real-world applications.
Entropy
Entropy, denoted as \( S \), is a key concept in thermodynamics. It measures the disorder or randomness of a system. Importantly, entropy is a state function, which means it depends only on the current state of the system, not the path taken to reach it.

Why entropy matters:
  • Entropy helps explain the direction of spontaneous processes. In isolated systems, processes tend to increase the total entropy.
  • It is closely related to the second law of thermodynamics, which states that the total entropy of an isolated system can never decrease over time.
Entropy is also used to determine the efficiency of thermodynamic cycles, playing a crucial role in engines, refrigerators, and many other technologies.
Enthalpy
Enthalpy, represented by \( H \), is a measure of the total heat content in a system. It is particularly useful in processes occurring at constant pressure, such as chemical reactions. Like entropy, enthalpy is a state function, meaning it is determined by the state of the system.

Key points about enthalpy:
  • In chemical reactions, the change in enthalpy \( \Delta H \) can help determine if a reaction is endothermic (absorbing heat) or exothermic (releasing heat).
  • It allows us to understand and calculate the heat exchange with the surroundings, useful in designing energy-efficient systems.
  • Enthalpy simplifies the analysis of processes, particularly when dealing with pressure-volume work.
In essence, enthalpy helps predict energy changes and is an integral part of both academic studies and practical applications.
Temperature
Temperature, denoted \( T \), is a fundamental concept in thermodynamics. It is a measure of the average kinetic energy of particles in a system and is essential for understanding heat and thermal energy. Temperature is a state function, meaning it relies solely on the present state of the system.

Significance of temperature:
  • Temperature provides a quantifiable measure for thermal energy which is pivotal in understanding heat transfer and thermodynamic processes.
  • It establishes thermal equilibrium between systems. Two systems in thermal contact are in equilibrium when they are at the same temperature.
  • Temperature scales like Celsius, Fahrenheit, and Kelvin are used universally, which help in standardizing measurements in scientific experiments and everyday life.
Comprehending temperature is vital for explaining how heat transfer occurs and how it impacts the behavior of different materials and processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The molar heat of vaporization of ethanol is \(39.3 \mathrm{~kJ} / \mathrm{mol}\), and the boiling point of ethanol is \(78.3^{\circ} \mathrm{C}\). Calculate \(\Delta S\) for the vaporization of 0.50 mole of ethanol.

Consider two carboxylic acids (acids that contain the \(-\) COOH group \(): \mathrm{CH}_{3} \mathrm{COOH}\) (acetic acid, \(\left.K_{\mathrm{a}}=1.8 \times 10^{-5}\right)\) and \(\mathrm{CH}_{2} \mathrm{ClCOOH}\) (chloroacetic acid, \(K_{\mathrm{a}}=1.4 \times 10^{-3}\) ). (a) Calculate \(\Delta G^{\circ}\) for the ionization of these acids at \(25^{\circ} \mathrm{C}\). (b) From the equation \(\Delta G^{\circ}=\Delta H^{\circ}-T \Delta S^{\circ},\) we see that the contributions to the \(\Delta G^{\circ}\) term are an enthalpy term \(\left(\Delta H^{\circ}\right)\) and a temperature times entropy term \(\left(T \Delta S^{\circ}\right)\). These contributions are listed here for the two acids: \begin{tabular}{lcc} & \(\Delta \boldsymbol{H}^{\circ}(\mathbf{k} \mathbf{J} / \mathbf{m o l})\) & \(T \Delta S^{\circ}(\mathbf{k} \mathbf{J} / \mathbf{m o l})\) \\ \hline \(\mathrm{CH}_{3} \mathrm{COOH}\) & -0.57 & -27.6 \\\ \(\mathrm{CH}_{2} \mathrm{ClCOOH}\) & -4.7 & -21.1 \end{tabular} Which is the dominant term in determining the value of \(\Delta G^{\circ}\) (and hence \(K_{\mathrm{a}}\) of the acid)? (c) What processes contribute to \(\Delta H^{\circ} ?\) (Consider the ionization of the acids as a Bronsted acid-base reaction.) (d) Explain why the \(T \Delta S^{\circ}\) term is more negative for \(\mathrm{CH}_{3} \mathrm{COOH} .\)

Describe two ways that you could determine \(\Delta G^{\circ}\) of a reaction.

From the following combinations of \(\Delta H\) and \(\Delta\) 3, predict if a process will be spontaneous at a high or low temperature: (a) both \(\Delta H\) and \(\Delta S\) are negative, (b) \(\Delta H\) is negative and \(\Delta S\) is positive, \((\mathrm{c})\) both \(\Delta H\) and \(\Delta S\) are positive, (d) \(\Delta H\) is positive and \(\Delta S\) is negative.

How does the entropy of a system change for each of the following processes? (a) A solid melts. (b) A liquid freezes. (c) A liquid boils. (d) A vapor is converted to a solid. (e) A vapor condenses to a liquid. (f) A solid sublimes. (g) A solid dissolves in water.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free