Chapter 18: Problem 55
Predict the signs of \(\Delta H, \Delta S,\) and \(\Delta G\) of the system for the following processes at 1 atm: (a) ammonia melts at \(-60^{\circ} \mathrm{C},(\mathrm{b})\) ammonia melts at \(-77.7^{\circ} \mathrm{C},(\mathrm{c})\) ammonia melts at \(-100^{\circ} \mathrm{C}\). (The normal melting point of ammonia is \(-77.7^{\circ} \mathrm{C}\).)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Enthalpy
- **Positive \( \Delta H \)**: Energy is absorbed during melting, indicating it takes energy to transform solid ammonia to liquid.
When predicting enthalpy changes, remember:
- **Endothermic**: \( \Delta H > 0 \)
- **Exothermic**: \( \Delta H < 0 \)
Entropy
- **Positive \( \Delta S \)**: The system becomes more disordered.
- **Increase in disorder**: \( \Delta S > 0 \)
- **Decrease in disorder**: \( \Delta S < 0 \)
Gibbs Free Energy
In our case of melting ammonia, \( \Delta G \) provides insight:
- **Negative \( \Delta G \)**: The process is spontaneous, as seen when melting above the melting point.
- **Zero \( \Delta G \)**: Indicates equilibrium, like melting at the exact melting point.
- **Positive \( \Delta G \)**: The process is non-spontaneous, needing additional energy, as with melting below the melting point.
Phase Changes
- **Melting**: Solid to liquid, increasing both \( \Delta H \) and \( \Delta S \).
- **Above melting point**: Substances melt spontaneously.
- **At melting point**: System is at equilibrium; neither spontaneous nor non-spontaneous.
- **Below melting point**: Requires external energy; non-spontaneous melting.