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Why is it more convenient to predict the direction of a reaction in terms of \(\Delta G_{\mathrm{sys}}\) instead of \(\Delta S_{\text {univ }}\) ? Under what conditions can \(\Delta G_{\mathrm{sys}}\) be used to predict the spontaneity of a reaction?

Short Answer

Expert verified
\( \Delta G_{\mathrm{sys}} \) predicts reaction direction more directly. It works under constant temperature and pressure.

Step by step solution

01

Understanding \\Delta G_{\mathrm{sys}} and \\Delta S_{\text {univ }}

The Gibbs free energy change \( \Delta G_{\mathrm{sys}} \) is a thermodynamic quantity that combines enthalpy \( \Delta H \) and entropy \( \Delta S \) changes of a system. In contrast, \( \Delta S_{\text {univ }} \) represents the change in entropy of the universe, combining both the system and surroundings. \( \Delta G_{\mathrm{sys}} \) directly relates to the tendencies of a reaction under constant temperature and pressure conditions, whereas \( \Delta S_{\text {univ }} \) is broader and less practical for immediate predictions.
02

Using \( \Delta G_{\mathrm{sys}} \) for Direction Prediction

Predictions made using \( \Delta G_{\mathrm{sys}} \) are more convenient because it simplifies the assessment: a negative \( \Delta G_{\mathrm{sys}} \) indicates a spontaneous reaction, whereas a positive \( \Delta G_{\mathrm{sys}} \) indicates non-spontaneity. This criterion is more direct than calculating \( \Delta S_{\text {univ }} \) because it doesn't require the separate calculation of entropy changes in both the system and surroundings.
03

Conditions for \( \Delta G_{\mathrm{sys}} \) Usage

\( \Delta G_{\mathrm{sys}} \) can be used to predict the spontaneity of a reaction under conditions where temperature and pressure are constant. This is typically applicable in many laboratory and industrial settings, allowing for straightforward determinations of whether a reaction will occur spontaneously.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is a fundamental concept that deals with energy and its transformations. In the context of chemical reactions, it explains how and why reactions occur. There are three main laws of thermodynamics, but in chemical reactions, we focus mainly on the first and second laws.
  • The first law is about energy conservation, implying energy cannot be created or destroyed, only transformed.
  • The second law introduces the concept of entropy, a measure of disorder or randomness, indicating that systems naturally progress toward greater disorder.
These principles help us understand how energy changes during reactions and why certain processes happen spontaneously while others do not.
Thermodynamics offers a framework to predict whether a reaction is energetically favorable based on energy changes within the system.
Spontaneity Prediction
Predicting whether a reaction will happen spontaneously is crucial in chemistry. We use the Gibbs free energy change (\( \Delta G_{\mathrm{sys}} \)) to make this prediction easily. This value tells us about the energy available to do work during a reaction.
  • If \( \Delta G_{\mathrm{sys}} \) is negative, the reaction is spontaneous, meaning it can occur without external input.
  • If it is positive, the reaction is non-spontaneous, requiring energy from an external source.
This method simplifies the process because it directly relates to conditions where temperature and pressure are constant. This makes \( \Delta G_{\mathrm{sys}} \) a more practical tool than calculating the universal entropy change \( \Delta S_{\text{univ}} \).
Gibbs free energy is an all-in-one measure that delights chemists by streamlining calculations and predictions.
Enthalpy and Entropy
The concepts of enthalpy and entropy are intertwined with Gibbs free energy. Enthalpy (\( \Delta H \)) refers to the total heat content of a system and is crucial for energy balance.
  • Positive \( \Delta H \) indicates the reaction absorbs heat (endothermic).
  • Negative \( \Delta H \) indicates the reaction releases heat (exothermic).
Entropy (\( \Delta S \)), on the other hand, is about disorder. A positive \( \Delta S \) means increased disorder, adding to the spontaneity.
Incorporating both into \( \Delta G \) with the equation:\[\Delta G = \Delta H - T \Delta S\]allows for a comprehensive assessment of a reaction's likelihood to proceed spontaneously.
Understanding how these variables interact provides valuable insight into the energetic feasibility of chemical processes.

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Most popular questions from this chapter

Hydrogenation reactions (e.g., the process of converting \(\mathrm{C}=\mathrm{C}\) bonds to \(\mathrm{C}-\mathrm{C}\) bonds in the food industry) are facilitated by the use of a transition metal catalyst, such as \(\mathrm{Ni}\) or \(\mathrm{Pt}\). The initial step is the adsorption, or binding, of hydrogen gas onto the metal surface. Predict the signs of \(\Delta H, \Delta S,\) and \(\Delta G\) when hydrogen gas is adsorbed onto the surface of Ni metal.

A certain reaction is known to have a \(\Delta G^{\circ}\) value of \(-122 \mathrm{~kJ} / \mathrm{mol}\). Will the reaction necessarily occur if the reactants are mixed together?

A \(74.6-\mathrm{g}\) ice cube floats in the Arctic Sea. The pressure and temperature of the system and surroundings are at 1 atm and \(0^{\circ} \mathrm{C},\) respectively. Calculate \(\Delta S_{\mathrm{sys}}, \Delta S_{\mathrm{surr}}\) and \(\Delta S_{\text {univ }}\) for the melting of the ice cube. What can you conclude about the nature of the process from the value of \(\Delta S_{\text {univ }}\) ? (The molar heat of fusion of water is \(6.01 \mathrm{~kJ} / \mathrm{mol} .\) )

Describe two ways that you could determine \(\Delta G^{\circ}\) of a reaction.

Consider two carboxylic acids (acids that contain the \(-\) COOH group \(): \mathrm{CH}_{3} \mathrm{COOH}\) (acetic acid, \(\left.K_{\mathrm{a}}=1.8 \times 10^{-5}\right)\) and \(\mathrm{CH}_{2} \mathrm{ClCOOH}\) (chloroacetic acid, \(K_{\mathrm{a}}=1.4 \times 10^{-3}\) ). (a) Calculate \(\Delta G^{\circ}\) for the ionization of these acids at \(25^{\circ} \mathrm{C}\). (b) From the equation \(\Delta G^{\circ}=\Delta H^{\circ}-T \Delta S^{\circ},\) we see that the contributions to the \(\Delta G^{\circ}\) term are an enthalpy term \(\left(\Delta H^{\circ}\right)\) and a temperature times entropy term \(\left(T \Delta S^{\circ}\right)\). These contributions are listed here for the two acids: \begin{tabular}{lcc} & \(\Delta \boldsymbol{H}^{\circ}(\mathbf{k} \mathbf{J} / \mathbf{m o l})\) & \(T \Delta S^{\circ}(\mathbf{k} \mathbf{J} / \mathbf{m o l})\) \\ \hline \(\mathrm{CH}_{3} \mathrm{COOH}\) & -0.57 & -27.6 \\\ \(\mathrm{CH}_{2} \mathrm{ClCOOH}\) & -4.7 & -21.1 \end{tabular} Which is the dominant term in determining the value of \(\Delta G^{\circ}\) (and hence \(K_{\mathrm{a}}\) of the acid)? (c) What processes contribute to \(\Delta H^{\circ} ?\) (Consider the ionization of the acids as a Bronsted acid-base reaction.) (d) Explain why the \(T \Delta S^{\circ}\) term is more negative for \(\mathrm{CH}_{3} \mathrm{COOH} .\)

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