Chapter 17: Problem 87
The \(\mathrm{p} K_{\mathrm{a}}\) of the indicator methyl orange is \(3.46 .\) Over what \(\mathrm{pH}\) range does this indicator change from 90 Dercent HIn to 90 percent In \(^{-}\) ?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson-Hasselbalch equation
\[ pH = pK_a + \log\left( \frac{[A^-]}{[HA]} \right) \]
Here, \( pK_a \) is the acid dissociation constant, \([A^-]\) is the concentration of the base form, and \([HA]\) is the concentration of the acid form of the indicator. This equation helps you find the pH at which an acid (HA) is half-neutralized, resulting in equal concentrations of HA and A⁻.
- When the concentration of the base form \([A^-]\) increases, pH increases.
- When the concentration of the acid form \([HA]\) increases, pH decreases.
pH range
For methyl orange, the transition from 90% protonated form (HIn) to 90% deprotonated form (In⁻) occurs between a pH of approximately 2.51 and 4.41. This specific range is determined using the Henderson-Hasselbalch equation by considering the ratio of the concentrations of the deprotonated and protonated forms of the indicator.
- A lower pH (2.51) indicates a greater concentration of the protonated form (HIn), meaning it remains in its acidic form.
- A higher pH (4.41) indicates a greater concentration of the deprotonated form (In⁻), meaning it turns to its basic form.
acid-base indicator
Indicators work on the principle of indicating the endpoint of a titration, providing a visible signal of the completion of the reaction. Methyl orange is red in acidic solutions and changes to yellow as the solution becomes more basic. Unlike some other indicators, it is best used in a slightly acidic medium.
- In a strongly acidic solution, methyl orange appears red.
- As the solution moves to a slightly basic condition, it turns yellow.
protonation state
When methyl orange is in its protonated state (HIn), it typically appears red. As the pH increases, the environment favors the loss of a proton, converting methyl orange to its deprotonated form (In⁻), where it takes on a yellow color.
- The protonation state at pH 2.51 shows 90% of methyl orange is in the HIn form.
- At pH 4.41, 90% of methyl orange is in the In⁻ form.