Chapter 17: Problem 76
Both \(\mathrm{Ag}^{+}\) and \(\mathrm{Zn}^{2+}\) form complex ions with \(\mathrm{NH}_{3}\). Write balanced equations for the reactions. However, \(\mathrm{Zn}(\mathrm{OH})_{2}\) is soluble in \(6 \mathrm{M} \mathrm{NaOH},\) and \(\mathrm{AgOH}\) is not. Explain.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
silver-ammonia complex
- Formation: Two ammonia molecules link with one silver ion.
- Stability: This complex ion is quite stable in solution.
zinc-ammonia complex
- Formation: Four ammonia molecules coordinate around the zinc ion.
- Solubility: These complex ions are soluble in water, impacting the overall solubility of zinc compounds.
amphoterism
Why is Zinc Hydroxide Amphoteric?
- Dual reactivity: Zinc hydroxide can dissolve in acids to form zinc salts, and in strong bases like \(6\ \mathrm{M}\ \mathrm{NaOH}\) to form zincate ions.
- Chemical reaction: In the presence of bases, zinc hydroxide converts to zincate, as shown:\[ \mathrm{Zn(OH)}_2 + 2\, \mathrm{OH}^{-} \rightarrow [\mathrm{Zn(OH)}_4]^{2-} \]
solubility
Comparing Zinc and Silver Hydroxide
- Zinc Hydroxide: Thanks to its amphoteric nature, it readily dissolves in basic solutions, forming soluble zincate ions.
- Silver Hydroxide: Lacks amphoterism and won't dissolve in a strong base, staying as a precipitate.
balanced chemical equations
Importance in Chemistry
- Predicting Products: Balanced equations help determine the products formed in a reaction.
- Quantification: They allow chemists to calculate how much of each substance is involved.