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Both \(\mathrm{Ag}^{+}\) and \(\mathrm{Zn}^{2+}\) form complex ions with \(\mathrm{NH}_{3}\). Write balanced equations for the reactions. However, \(\mathrm{Zn}(\mathrm{OH})_{2}\) is soluble in \(6 \mathrm{M} \mathrm{NaOH},\) and \(\mathrm{AgOH}\) is not. Explain.

Short Answer

Expert verified
\(\mathrm{Ag}^{+}\) forms \([\mathrm{Ag}(\mathrm{NH}_{3})_2]^{+}\), \(\mathrm{Zn}^{2+}\) forms \([\mathrm{Zn}(\mathrm{NH}_{3})_4]^{2+}\), \(\mathrm{Zn(OH)}_2\) is amphoteric and dissolves in NaOH, \(\mathrm{AgOH}\) is not.

Step by step solution

01

Write Ag+ and NH3 Complex Equation

Silver ion, \(\mathrm{Ag}^{+}\), reacts with ammonia, \(\mathrm{NH}_{3}\), to form the diamminesilver complex ion. The balanced equation for this reaction is:\[ \mathrm{Ag}^{+} + 2\ \mathrm{NH}_{3} \rightarrow [\mathrm{Ag}(\mathrm{NH}_{3})_2]^{+} \]
02

Write Zn2+ and NH3 Complex Equation

Zinc ion, \(\mathrm{Zn}^{2+}\), reacts with ammonia to form the complex ion tetraamminezinc. The balanced equation is:\[ \mathrm{Zn}^{2+} + 4\ \mathrm{NH}_{3} \rightarrow [\mathrm{Zn}(\mathrm{NH}_{3})_4]^{2+} \]
03

Zn(OH)2 Solubility in NaOH

Zinc hydroxide, \(\mathrm{Zn(OH)}_2\), is amphoteric and dissolves in both acids and bases. In \(6\ \mathrm{M}\ \mathrm{NaOH}\), it further reacts to form the soluble zincate ion:\[ \mathrm{Zn(OH)}_2 + 2\ \mathrm{OH}^{-} \rightarrow [\mathrm{Zn(OH)}_4]^{2-} \]
04

AgOH Insolubility in NaOH

Silver hydroxide, \(\mathrm{AgOH}\), is not amphoteric and does not form complex ions with hydroxide. It remains insoluble under basic conditions and precipitates out as \(\mathrm{AgOH}\).
05

Conclusion

The solubility difference is because \(\mathrm{Zn(OH)}_2\) is amphoteric and can form soluble complexes with hydroxide ions, whereas \(\mathrm{AgOH}\), lacking amphoteric behavior, remains insoluble.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

silver-ammonia complex
Silver ions can interact with ammonia in an interesting way. When \(\mathrm{Ag}^{+}\) ions are mixed with ammonia \(\mathrm{NH}_{3}\), they form a compound known as a complex ion. Specifically, this creates the diamminesilver complex ion. This transformation can be expressed in the balanced chemical equation: \[ \mathrm{Ag}^{+} + 2\, \mathrm{NH}_{3} \rightarrow [\mathrm{Ag}(\mathrm{NH}_{3})_2]^{+} \]Here's how it works:
  • Formation: Two ammonia molecules link with one silver ion.
  • Stability: This complex ion is quite stable in solution.
Understanding the behavior of silver ions with ammonia is crucial, especially in understanding solubility and reactions in different chemical environments.
zinc-ammonia complex
Similar to silver, zinc ions \(\mathrm{Zn}^{2+}\) can also react with ammonia. However, zinc forms a different kind of complex ion. The reaction produces the tetraamminezinc complex, as shown by the equation:\[\mathrm{Zn}^{2+} + 4\, \mathrm{NH}_{3} \rightarrow [\mathrm{Zn}(\mathrm{NH}_{3})_4]^{2+}\]Key aspects of this reaction:
  • Formation: Four ammonia molecules coordinate around the zinc ion.
  • Solubility: These complex ions are soluble in water, impacting the overall solubility of zinc compounds.
Zinc's ability to form complex ions helps to explain its different reactivity patterns, especially when comparing with other metals like silver.
amphoterism
Amphoterism is a unique characteristic of certain compounds and metals, like zinc hydroxide. An amphoteric substance can react with both acids and bases. This is a key idea to understand how zinc compounds behave in different environments.

Why is Zinc Hydroxide Amphoteric?

  • Dual reactivity: Zinc hydroxide can dissolve in acids to form zinc salts, and in strong bases like \(6\ \mathrm{M}\ \mathrm{NaOH}\) to form zincate ions.
  • Chemical reaction: In the presence of bases, zinc hydroxide converts to zincate, as shown:\[ \mathrm{Zn(OH)}_2 + 2\, \mathrm{OH}^{-} \rightarrow [\mathrm{Zn(OH)}_4]^{2-} \]
This property has wide-ranging implications for zinc's chemical applications and highlights a big difference compared to other non-amphoteric compounds.
solubility
Solubility refers to the ability of a substance to dissolve in a solvent, typically water for most chemistry problems. It's fascinating because solubility can vastly change based on chemical properties, like amphoterism.

Comparing Zinc and Silver Hydroxide

  • Zinc Hydroxide: Thanks to its amphoteric nature, it readily dissolves in basic solutions, forming soluble zincate ions.
  • Silver Hydroxide: Lacks amphoterism and won't dissolve in a strong base, staying as a precipitate.
Understanding solubility helps predict the behavior of various substances in different chemical conditions, and can even influence how they're used in industrial and laboratory settings.
balanced chemical equations
A balanced chemical equation is crucial for accurately representing a chemical reaction. It ensures that the law of conservation of mass is respected, meaning the same number of atoms are seen on each side of the equation.

Importance in Chemistry

  • Predicting Products: Balanced equations help determine the products formed in a reaction.
  • Quantification: They allow chemists to calculate how much of each substance is involved.
For instance, knowing the balance in the formation of complex ions helps understand reaction mechanisms and possible applications thereof.

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Most popular questions from this chapter

In principle, amphoteric oxides, such as \(\mathrm{Al}_{2} \mathrm{O}_{3}\) and \(\mathrm{BeO}\) can be used to prepare buffer solutions because they possess both acidic and basic properties (see Section 16.11). Explain why these compounds are of little practical use as buffer components.

A diprotic acid, \(\mathrm{H}_{2} \mathrm{~A}\), has the following ionization constants: \(K_{\mathrm{a}_{1}}=1.1 \times 10^{-3}\) and \(K_{\mathrm{a}_{2}}=2.5 \times 10^{-6}\) To make up a buffer solution of \(\mathrm{pH} 5.80,\) which combination would you choose: \(\mathrm{NaHA} / \mathrm{H}_{2} \mathrm{~A}\) or Na A/NaHA?

Sketch the titration curve of a weak acid with a strong base like the one shown in Figure 17.4 . On your graph, indicate the volume of base used at the equivalence point and also at the half-equivalence point, that is, the point at which half of the acid has been neutralized. Explain how the measured \(\mathrm{pH}\) at the half-equivalence point can be used to determine \(K_{\mathrm{a}}\) of the acid.

The \(\mathrm{p} K_{\mathrm{a}}\) of phenolphthalein is \(9.10 .\) Over what \(\mathrm{pH}\) range does this indicator change from 95 percent HIn to 95 percent \(\mathrm{In}^{-} ?\)

\(\mathrm{CaSO}_{4}\left(K_{\mathrm{sp}}=2.4 \times 10^{-5}\right)\) has a larger \(K_{\mathrm{sp}}\) value than that of \(\mathrm{Ag}_{2} \mathrm{SO}_{4}\left(K_{\mathrm{sp}}=1.4 \times 10^{-5}\right)\). Does it necessarily follow that \(\mathrm{CaSO}_{4}\) also has greater solubility \((\mathrm{g} / \mathrm{L}) ?\) Explain.

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