Chapter 17: Problem 39
The ionization constant \(K_{\mathrm{a}}\) of an indicator HIn is \(1.0 \times 10^{-6} .\) The color of the nonionized form is red and that of the ionized form is yellow. What is the color of this indicator in a solution whose \(\mathrm{pH}\) is \(4.00 ?\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionization Constant
pH Calculations
- The pH can be calculated using the formula: \(pH = -\log[\text{H}^+]\).
- In our situation, a solution with a pH of 4.00 corresponds to a hydronium ion concentration of \([\text{H}^+] = 10^{-4} \text{ M}\).
Color Change in Indicators
- At low pH, indicators tend to be in their non-ionized form, while high pH favors the ionized form.
- For the indicator HIn, red represents the non-ionized form, and yellow represents the ionized form.