Chapter 16: Problem 94
Predict the relative acid strengths of the following compounds: \(\mathrm{H}_{2} \mathrm{O}, \mathrm{H}_{2} \mathrm{~S},\) and \(\mathrm{H}_{2} \mathrm{Se}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Periodic Trends
Acid strength tends to increase as you move down a group in the periodic table, such as Group 16. This is due to the increasing size of atoms. Larger atoms form weaker bonds with hydrogen, allowing the easier release of a proton (\(\mathrm{H}^+\)) which results in increased acidity.
- As you move downwards, atomic size increases.
- Larger atoms result in weaker bonds with hydrogen.
- Weaker bonds enable easier ionization, enhancing acid strength.
Hydrides
In the context of Group 16 elements, hydrides such as \(\mathrm{H}_2\mathrm{O}\), \(\mathrm{H}_2\mathrm{~S}\), and \(\mathrm{H}_2\mathrm{Se}\) show a clear trend in acid strength.
- \(\mathrm{H}_2\mathrm{O}\) is a weak acid because its oxygen-hydrogen bond is relatively strong, preventing the easy release of \(\mathrm{H}^+\).
- \(\mathrm{H}_2\mathrm{~S}\) is stronger than water, as sulfur's larger atomic radius weakens its bond with hydrogen.
- The strongest among these is \(\mathrm{H}_2\mathrm{Se}\), where selenium's even larger size further weakens the hydrogen bond.
Group 16 Elements
As you progress down the group, each element typically displays increased atomic and ionic size leading to various effects, including those on their hydrides' acid strengths.
- Atomic radius increases from oxygen to polonium.
- The increase in atomic size leads to decreased bond strength with hydrogen.
- This decrease results in easier \(\mathrm{H}^+\) dissociation and hence increased acidity.