Chapter 16: Problem 78
From the relationship \(K_{\mathrm{a}} K_{\mathrm{b}}=K_{\mathrm{w}},\) what can you deduce about the relative strengths of a weak acid and its conjugate base?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Weak Acid
If \( K_a \) is less than 1, the acid is considered weak since it indicates a low tendency to lose protons and form its conjugate base. Weak acids are very common, with examples including acetic acid (found in vinegar) and citric acid (found in citrus fruits).
Remember:
- A smaller \( K_a \) means weaker acid strength.
- Weak acids partially dissociate in solution.
- They are in a chemical equilibrium between the acid and its ions.
Conjugate Base
For weak acids, the conjugate base tends to be stronger than its counterpart from a strong acid. This means that the base is more likely to re-associate with a proton. However, even the conjugate bases of weak acids are still weak compared to strong bases like hydroxides.
Key Points:
- The conjugate base of a weak acid is moderately strong.
- It is in equilibrium with the weak acid in the solution.
- The relative strength is determined by the base dissociation constant, \( K_b \).
Dissociation Constant
For a weak acid:
\[K_a = \frac{[H^+][A^-]}{[HA]}\]
Here, \( [H^+] \) is the concentration of hydrogen ions, \( [A^-] \) is the concentration of the conjugate base, and \( [HA] \) is the concentration of the undissociated acid. A low \( K_a \) signifies a weak acid, while a low \( K_b \) signifies a weak conjugate base.
Essential Aspects:
- \( K_a \) and \( K_b \) are inversely related as they multiply to give \( K_w \), the ionic product of water.
- These constants provide insight into the acid and base strength and their behavior.
Ionic Product of Water
This constant arises from the self-ionization of water, which can be represented as:
\[H_2O(l) \rightleftharpoons H^+(aq) + OH^-(aq)\]
For pure water, the concentrations of hydrogen ions \([H^+]\) and hydroxide ions \([OH^-]\) are equal, leading to:
\[K_w = [H^+][OH^-] = 1.0 \times 10^{-14} \]
Important Takeaways:
- \( K_w \) helps in calculating the pH and pOH of solutions.
- It is the product of respective dissociation constants \( K_a \) for acids and \( K_b \) for bases, such that \( K_a \times K_b = K_w \).