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The \(\mathrm{pOH}\) of a solution is 9.40 at \(25^{\circ} \mathrm{C}\). Calculate the hydronium ion concentration of the solution.

Short Answer

Expert verified
The hydronium ion concentration is approximately \(2.51 \times 10^{-5}\) M.

Step by step solution

01

Understand the relationship between pOH and pH

The relationship between pH and pOH is given by the equation: \( \mathrm{pH} + \mathrm{pOH} = 14 \). At \(25^{\circ} \mathrm{C} \), this equation allows us to find the \( \mathrm{pH} \) if we know the \( \mathrm{pOH} \).
02

Calculate the pH of the solution

Given \( \mathrm{pOH} = 9.40 \), use the relationship: \( \mathrm{pH} = 14 - \mathrm{pOH} = 14 - 9.40 = 4.60 \). Now we know the pH of the solution is 4.60.
03

Understand the relationship between pH and hydronium ion concentration

The pH of a solution is related to the hydronium ion concentration \( [\mathrm{H}_3\mathrm{O}^+] \) by the formula: \( \mathrm{pH} = -\log_{10}([\mathrm{H}_3\mathrm{O}^+]) \). We can use this to find the hydronium ion concentration after calculating the pH.
04

Calculate hydronium ion concentration

Rearrange the formula to solve for \([\mathrm{H}_3\mathrm{O}^+]\): \([\mathrm{H}_3\mathrm{O}^+] = 10^{-\mathrm{pH}} \). Using \( \mathrm{pH} = 4.60 \), we find \([\mathrm{H}_3\mathrm{O}^+] = 10^{-4.60} \approx 2.51 \times 10^{-5} \text{ M} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pOH
The \(\mathrm{pOH}\) of a solution provides insight into its basicity. It measures the concentration of hydroxide ions (OH⁻) in a solution. The formula to calculate \(\mathrm{pOH}\) is \(\mathrm{pOH} = -\log_{10}([\mathrm{OH}^-])\). This logarithmic scale is similar to \(\mathrm{pH}\) and is used to understand the acidic or basic nature of a solution.
When dealing with \(\mathrm{pOH}\), you should know:
  • The lower the \(\mathrm{pOH}\), the more basic the solution is.
  • To switch between \(\mathrm{pH}\) and \(\mathrm{pOH}\), you can use the formula: \(\mathrm{pH} + \mathrm{pOH} = 14\).
  • This relationship is valid in water at \(25^{\circ} \mathrm{C}\).

For the solution with a \(\mathrm{pOH}\) of 9.40, you can use these basics to find out more about its acidic counterparts, specifically the \(\mathrm{pH}\) and the hydronium ion concentration.
pH
The \(\mathrm{pH}\) of a solution is a measure of the concentration of hydrogen ions (H⁺) or hydronium ions \(\left(\mathrm{H}_3\mathrm{O}^+\right)\). It indicates how acidic or basic a solution is, using a scale from 0 to 14. The formula used is \(\mathrm{pH} = -\log_{10}([\mathrm{H}_3\mathrm{O}^+])\).
Here are some key points about \(\mathrm{pH}\):
  • If the \(\mathrm{pH}\) is less than 7, the solution is acidic.
  • If the \(\mathrm{pH}\) is greater than 7, the solution is basic.
  • A \(\mathrm{pH}\) of 7 is considered neutral, as is the case with pure water.

In our example, once we calculated the \(\mathrm{pH}\) from a \(\mathrm{pOH}\) of 9.40 (which turned out to be 4.60), we could then determine that the solution is acidic. From the \(\mathrm{pH}\), calculations can be done to determine the hydronium ion concentration.
Relationship between pH and pOH
The relationship between \(\mathrm{pH}\) and \(\mathrm{pOH}\) is a fundamental aspect of acid-base chemistry. The equation \(\mathrm{pH} + \mathrm{pOH} = 14\) expresses this balance in any aqueous solution at \(25^{\circ} \mathrm{C}\).
Understanding this relationship helps in:
  • Interconverting between \(\mathrm{pH}\) and \(\mathrm{pOH}\).
  • Assessing the acidity or basicity of a solution quickly by knowing either value.

This relationship ensures that if you know one value, you can effortlessly deduce the other. For instance, with a \(\mathrm{pOH}\) of 9.40, the \(\mathrm{pH}\) calculates as 4.60. This knowledge is key in tackling a variety of chemical problems, particularly when determining the characteristics of an unknown solution.
Acid-base equilibria
Acid-base equilibria involve reactions that establish the balance between acids and bases in a solution. The essence of these equilibria lies in understanding the exchange of protons \(\left(\mathrm{H}^+\right)\) between acids and bases. \(\mathrm{pH}\) and \(\mathrm{pOH}\) values are central to analyzing such equilibria, detailing how acidic or basic a given solution is.
Consider the following aspects when exploring acid-base equilibria:
  • Equilibrium constant expressions denote the extent of ionization of acids or bases.
  • A strong acid fully ionizes in water, while a weak acid only partially does so.
  • These equilibria help predict how changing concentrations or conditions affects the solution.

Being well-versed in acid-base equilibria allows one to predict the effects of adding acids or bases to solutions, further informing the pH or pOH changes. These reactions are at the heart of many natural and industrial processes, making comprehension vital for students and professionals alike.

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Most popular questions from this chapter

\(\mathrm{HF}\) is a weak acid, but its strength increases with concentration. Explain. (Hint: \(\mathrm{F}^{-}\) reacts with \(\mathrm{HF}\) to form \(\mathrm{HF}_{2}^{-}\). The equilibrium constant for this reaction is 5.2 at \(25^{\circ} \mathrm{C} .\) )

Hemoglobin (Hb) is a blood protein that is responsible for transporting oxygen. It can exist in the protonated form as \(\mathrm{HbH}^{+}\). The binding of oxygen can be represented by the simplified equation: $$ \mathrm{HbH}^{+}+\mathrm{O}_{2} \rightleftharpoons \mathrm{HbO}_{2}+\mathrm{H}^{+} $$ (a) What form of hemoglobin is favored in the lungs where oxygen concentration is highest? (b) In body tissues, where the cells release carbon dioxide produced by metabolism, the blood is more acidic due to the formation of carbonic acid. What form of hemoglobin is favored under this condition? (c) When a person hyperventilates, the concentration of \(\mathrm{CO}_{2}\) in his or her blood decreases. How does this action affect the given equilibrium? Frequently a person who is hyperventilating is advised to breathe into a paper bag. Why does this action help the individual?

A \(0.015-M\) solution of a monoprotic acid is 0.92 percent ionized. Calculate the ionization constant for the acid.

Why do we normally not quote \(K_{\mathrm{a}}\) values for strong acids such as \(\mathrm{HCl}\) and \(\mathrm{HNO}_{3}\) ? Why is it necessary to specify temperature when giving \(K_{a}\) values?

What is the original molarity of a solution of a weak acid whose \(K_{\mathrm{a}}\) is \(3.5 \times 10^{-5}\) and whose \(\mathrm{pH}\) is 5.26 at \(25^{\circ} \mathrm{C} ?\)

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