Chapter 16: Problem 131
To which of the following would the addition of an equal volume of \(0.60 \mathrm{M} \mathrm{NaOH}\) lead to a solution having (b) \(0.30 \mathrm{M} \mathrm{HCl}\) (c) \(0.70 \mathrm{M} \mathrm{KOH}\) a lower \(\mathrm{pH}\) : (a) water, (d) \(0.40 \mathrm{M} \mathrm{NaNO}_{3}\) ?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
pH Calculation
To calculate pH for strong acids and bases, we rely on the formula:
\[ pH = -\log [H^+] \]
For bases, we calculate pOH and then use the relationship:
\[ pH + pOH = 14 \]
- Adding a strong acid like HCl to water decreases the pH, making the solution acidic.
- Conversely, adding a strong base like NaOH increases the pH, creating a basic solution.
Neutralization Reaction
\[ ext{Acid} + ext{Base} \rightarrow ext{Salt} + ext{Water} \]
For instance, when NaOH is added to HCl, the strong base neutralizes the strong acid, resulting in water and sodium chloride (NaCl).
- This process is exothermic, releasing heat.
- The resulting solution is usually neutral, with pH approximately equating to 7.
Solution Molarity
To determine a solution's molarity after mixing different solutions, we often take an average or sum based on their respective concentrations. For example, mixing equal volumes of equal molar NaOH and KOH results in a solution of higher molarity:
\[ ext{Combined molarity} = rac{ ext{Molarity of NaOH} + ext{Molarity of KOH}}{2} \]
Understanding molarity helps us predict which of the resultant solutions will have higher or lower pH post mixing.
Basic Solutions
- Basic solutions turn red litmus paper blue.
- They often feel slippery to the touch due to the saponification reaction.
- They can neutralize acids to form water and salts, resulting in neutral or higher pH solutions.