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Predict the direction that predominates in this reaction: $$ \mathrm{F}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{HF}(a q)+\mathrm{OH}^{-}(a q) $$

Short Answer

Expert verified
The forward reaction is favored; equilibrium shifts towards \( \mathrm{HF}(aq) + \mathrm{OH}^{-}(aq) \).

Step by step solution

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01

Identify Reactants and Products

In this equilibrium reaction, we have \( \mathrm{F}^{-}(aq) \) and \( \mathrm{H}_{2}\mathrm{O}(l) \) as the reactants, and \( \mathrm{HF}(aq) \) and \( \mathrm{OH}^{-}(aq) \) as the products.
02

Evaluate Acid-Base Strength

Identify that \( \mathrm{HF} \) is a weak acid and \( \mathrm{OH^{-}} \), the conjugate base of water, is the conjugate base of a very weak acid. On the other hand, \( \mathrm{F^{-}} \) is the conjugate base of \( \mathrm{HF} \), and water (\( \mathrm{H_2O} \)) is acting as a weak acid here.
03

Predict Equilibrium Direction

The reaction tends to favor the side with the weaker acids and bases in an acid-base reaction. \( \mathrm{HF} \) is a weaker acid compared to water acting as an acid in this context. Thus, the equilibrium will predominately shift towards the formation of \( \mathrm{HF} \) and \( \mathrm{OH}^{-} \), meaning the forward reaction is favored.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weak Acids
A weak acid is an acid that does not completely dissociate in water. This means that in solution, both the acid and its dissociated ions exist in equilibrium. For example, hydrofluoric acid (HF) is a common weak acid. In water, it only partially breaks down into hydrogen ( +H^+ ) ions and fluoride ( F^- ) ions.
Why is HF considered a weak acid? - **Partial Dissociation:** Unlike strong acids, which fully ionize in solution, HF only disassociates slightly. - **Equilibrium Presence:** There is a dynamic balance between HF and its ions ( H^+ and F^- ).
The concept of weak acids is crucial in understanding acid-base equilibrium. In any reaction involving a weak acid, you must consider how the equilibrium will shift based on the relative strengths of the acids and bases involved.
Conjugate Base
The conjugate base of an acid is what remains after the acid donates a proton ( H^+ ). For every acid-base reaction, there is a corresponding conjugate acid-base pair. Understanding these pairs is key to predicting reaction behavior.
For example, in our reaction: - **HF becomes** F^- **on losing a proton** - **This makes F^- the conjugate base of HF**
To understand better: - The stronger an acid, the weaker its conjugate base. - Similarly, the weaker the acid, the stronger its conjugate base. In this situation, because HF is a weak acid, F^- is relatively strong as a conjugate base. This plays a role in determining which direction the equilibrium will shift in an acid-base reaction, as the interaction between acids and their conjugate bases helps drive that shift.
Equilibrium Direction
In any acid-base reaction, predicting equilibrium direction involves comparing the strengths of the acids and bases on both sides of the equation. Generally, the equilibrium will favor the side with the weaker acid and base because they are less likely to react further.
**Factors affecting equilibrium direction:** - **Acid and Base Strengths:** The side with the weaker acid ( HF ) and the weaker base ( OH^- ) is favored. - **Initial Concentrations and Conditions:** While not highlighted here, in more advanced scenarios initial conditions can also influence equilibrium direction.
For our reaction between F^- and H_2O , because HF is weaker compared to water acting as an acid, the equilibrium shifts to the right, towards the products ( HF and OH^- ). This is an essential principle for predicting the predominant direction of acid-base reactions.
Acid-Base Reaction
Acid-base reactions involve the transfer of protons ( H^+ ) between reactants. These reactions can be understood and predicted using the Brønsted-Lowry acid-base theory, which classifies acids as proton donors and bases as proton acceptors.
In our example: - F^- acts as the base: accepting a proton from water. - H_2O acts as an acid, donating a proton to form OH^- .
**Key aspects of acid-base reactions include:** - **Acid and Base Identification:** Determining which substances are acids and bases in the reaction. - **Conjugate Pairs:** Recognizing conjugate acid-base pairs formed during the reaction. - **Dynamic Equilibrium:** Understanding that these reactions reach a balance where the rate of the forward reaction equals the rate of the reverse reaction. Comprehending these fundamentals aids in mastering more complex acid-base interactions and predicting outcomes in varying chemical contexts.

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Most popular questions from this chapter

When the concentration of a strong acid is not substantially higher than \(1.0 \times 10^{-7} M\), the ionization of water must be taken into account in the calculation of the solution's \(\mathrm{pH}\). (a) Derive an expression for the \(\mathrm{pH}\) of a strong acid solution, including the contribution to \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) from \(\mathrm{H}_{2} \mathrm{O}\). (b) Calculate the pH of a \(1.0 \times 10^{-7} M \mathrm{HCl}\) solution.

Both the amide ion \(\left(\mathrm{NH}_{2}^{-}\right)\) and the nitride ion \(\left(\mathrm{N}^{3-}\right)\) are stronger bases than the hydroxide ion and hence do not exist in aqueous solutions. (a) Write equations showing the reactions of these ions with water, and identify the Brönsted acid and base in each case. (b) Which of the two is the stronger base?

Predict whether a solution containing the salt \(\mathrm{K}_{2} \mathrm{HPO}_{4}\) will be acidic, neutral, or basic.

Most of the hydrides of Group \(1 \mathrm{~A}\) and Group \(2 \mathrm{~A}\) metals are ionic (the exceptions are \(\mathrm{BeH}_{2}\) and \(\mathrm{MgH}_{2}\), which are covalent compounds). (a) Describe the reaction between the hydride ion \(\left(\mathrm{H}^{-}\right)\) and water in terms of a Brønsted acid-base reaction. (b) The same reaction can also be classified as a redox reaction. Identify the oxidizing and reducing agents.

Like water, liquid ammonia undergoes autoionization: $$ \mathrm{NH}_{3}+\mathrm{NH}_{3} \rightleftharpoons \mathrm{NH}_{4}^{+}+\mathrm{NH}_{2}^{-} $$ (a) Identify the Brönsted acids and Bronsted bases in this reaction. (b) What species correspond to \(\mathrm{H}_{3} \mathrm{O}^{+}\) and \(\mathrm{OH}^{-},\) and what is the condition for a neutral solution?

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