Chapter 15: Problem 91
When a gas was heated under atmospheric conditions, its color deepened. Heating above \(150^{\circ} \mathrm{C}\) caused the color to fade, and at \(550^{\circ} \mathrm{C}\) the color was barely detectable. However, at \(550^{\circ} \mathrm{C},\) the color was partially restored by increasing the pressure of the system. Which of the following best fits the preceding description: (a) a mixture of hydrogen and bromine, (b) pure bromine, (c) a mixture of nitrogen dioxide and dinitrogen tetroxide. (Hint: Bromine has a reddish color, and nitrogen dioxide is a brown gas. The other gases are colorless.) Justify your choice.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Le Chatelier's Principle
This principle plays a key role in understanding how nitrogen dioxide ( ext{NO}_2) and dinitrogen tetroxide ( ext{N}_2 ext{O}_4) interact, especially when conditions change.
- When temperature increases, the equilibrium between ext{NO}_2 and ext{N}_2 ext{O}_4 shifts to favor the endothermic reaction, which produces ext{NO}_2. This is why color changes occur.
- Increasing pressure will shift the equilibrium towards fewer moles of gas, thus favoring the formation of ext{N}_2 ext{O}_4 from ext{NO}_2.
Nitrogen Dioxide
In chemistry, ext{NO}_2 demonstrates interesting behaviors due to its equilibrium with dinitrogen tetroxide ( ext{N}_2 ext{O}_4). This equilibrium is temperature sensitive:
- At lower temperatures, more ext{N}_2 ext{O}_4 is present, and the gas appears lighter because ext{N}_2 ext{O}_4 is colorless.
- As temperatures rise, more ext{NO}_2 is formed, making the gas appear browner.
Dinitrogen Tetroxide
\[ \text{N}_2\text{O}_4(g) \rightleftharpoons 2\text{NO}_2(g) \]
In this reaction, ext{N}_2 ext{O}_4 can dissociate to form two molecules of ext{NO}_2, and vice versa. This equilibrium is strongly temperature and pressure-dependent. At lower temperatures, the equilibrium shifts towards the formation of ext{N}_2 ext{O}_4, which explains the fading color at higher temperatures noticed in the exercise.
Additionally, the behavior of ext{N}_2 ext{O}_4 solves the exercise by exploring the impact of pressure changes in a chemical system, thus confirming the observations made about gas color changes.
Temperature Effects
- An increase in temperature will generally shift the equilibrium towards the endothermic process. Here, it favors the breakdown of ext{N}_2 ext{O}_4 into ext{NO}_2, increasing the concentration of the brownish ext{NO}_2 gas.
- On cooling, the reverse happens, as more ext{N}_2 ext{O}_4 is favored, leading to a lighter coloration.
Pressure Effects
- When pressure increases, the equilibrium shifts from ext{2NO}_2 to ext{N}_2 ext{O}_4 because it involves fewer gas molecules (from 2 moles of ext{NO}_2 to 1 mole of ext{N}_2 ext{O}_4).
- This shift towards ext{N}_2 ext{O}_4 is why the color is restored when pressure is increased at high temperatures.