Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider the equilibrium: $$ 2 \mathrm{I}(g) \rightleftarrows \mathrm{I}_{2}(g) $$ What would be the effect on the position of equilibrium of (a) increasing the total pressure on the system by decreasing its volume, (b) adding \(\mathrm{I}_{2}\) to the reaction mixture, and (c) decreasing the temperature?

Short Answer

Expert verified
a) Right; b) Left; c) Right (assuming exothermic).

Step by step solution

01

Analyze Effect of Pressure Increase

When the total pressure is increased by decreasing the volume, according to Le Chatelier's Principle, the equilibrium will shift towards the side with fewer gas molecules to counteract the change. In the given reaction, \[ 2 \mathrm{I}(g) \rightleftarrows \mathrm{I}_{2}(g) \]there are more moles of gas on the left (2 moles of \(\mathrm{I}\)) than on the right (1 mole of \(\mathrm{I}_{2}\)). Thus, increasing pressure will shift the equilibrium to the right.
02

Effect of Adding I2

When \(\mathrm{I}_{2}\) is added to the mixture, the system will counteract the change by consuming some of the additional \(\mathrm{I}_{2}\). According to Le Chatelier's Principle, this will shift the equilibrium to the left, favoring the formation of \(\mathrm{I}\) gas.
03

Effect of Decreasing Temperature

The effect of changing temperature on equilibrium depends on whether the reaction is exothermic or endothermic. If the reaction is exothermic (which we assume here as a common condition for dimerization reactions like this), decreasing the temperature will shift the equilibrium towards the products, \(\mathrm{I}_{2}\), to release heat. Thus, the equilibrium position will shift to the right.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle helps us understand how a chemical equilibrium reacts to changes in conditions. It states that if a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the equilibrium will shift to counteract the imposed change and re-establish equilibrium. This principle is an essential tool for predicting the direction of the equilibrium shift under different experimental conditions.
  • For example, adding more of a reactant will typically shift the equilibrium toward the products.
  • Conversely, removing a product will also shift the balance toward the products to fill the void left.
Understanding this principle allows chemists to control the outcome of reactions by manipulating conditions to favor the production of desired substances.
Effect of Pressure on Equilibrium
The effect of pressure on chemical equilibrium is significant, especially for reactions involving gases. According to Le Chatelier's Principle, an increase in pressure by reducing volume causes the equilibrium to shift toward the side with fewer gas molecules.
In the reaction \[2 \mathrm{I}(g) \rightleftarrows \mathrm{I}_{2}(g)\]there are more moles of gaseous iodine on the left than iodine molecules on the right. Hence, increasing the pressure will push the equilibrium towards the side with fewer moles, which is the right side in this case, favoring the formation of iodine molecules \(\mathrm{I}_{2}\).
  • This shift reduces the total number of gas molecules, thus opposing the pressure increase.
  • Decreasing the pressure would result in the equilibrium shifting back to the left, favoring more gaseous iodine formation.
Effect of Temperature on Equilibrium
Temperature changes can have a profound effect on chemical equilibria. According to Le Chatelier's Principle, the equilibrium will shift in a direction that offsets the change in temperature. The reaction type, whether endothermic or exothermic, plays a crucial role in determining this shift.
  • In exothermic reactions, such as the dimerization of iodide, decreasing temperature favors the production of more products (\(\mathrm{I}_{2}(g)\)).
  • This is because the system releases heat, shifting the equilibrium to the right to produce more heat in response to the temperature drop.
If the reaction were endothermic, decreasing the temperature would result in shifting to the left, favoring the reactants.
Equilibrium Shift
An equilibrium shift occurs when a change, such as pressure, concentration, or temperature, is applied to a system in equilibrium. This shift attempts to counterbalance the change and re-establish equilibrium. Knowing the direction of these shifts helps predict the outcome of changes in reaction conditions.
In our example of \[2 \mathrm{I}(g) \rightleftarrows \mathrm{I}_{2}(g)\]- Adding \(\mathrm{I}_{2}\) increases the concentration of products, causing a shift to the left.- This makes more \(\mathrm{I}(g)\), as the system tries to reduce this added \(\mathrm{I}_{2}\) by converting it back into gases.
  • This mechanism underscores the dynamic nature of chemical equilibria, constantly adjusting to maintain balance.
Reaction Dynamics
Reaction dynamics focus on the factors that affect the speed and position of a reaction at equilibrium. These dynamics encompass temperature, pressure, and concentration changes, all of which are interrelated in influencing equilibrium.
- When altering conditions, an equilibrium's response can yield insights into the interaction of reactants and products. - Reaction dynamics also enable us to tailor conditions to favor desired equilibrium outcomes in industrial and laboratory processes.
  • For example, increasing pressure or decreasing the volume in gas-phase reactions can speed up the formation of products by shifting equilibrium optimally.
  • Similarly, temperature adjustments can be critical in maximizing yield for industrial chemical syntheses.
Recognizing how dynamics play into equilibrium shifts is vital for optimizing chemical processes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The "boat" form and the "chair" form of cyclohexane \(\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)\) interconvert as shown here: $$\underset{k_{-1}}{\stackrel{k_{1}}{\rightleftarrows}}$$ In this representation, the \(\mathrm{H}\) atoms are omitted and a \(\mathrm{C}\) atom is assumed to be at each intersection of two lines (bonds). The conversion is first order in each direction. The activation energy for the chair boat conversion is \(41 \mathrm{~kJ} / \mathrm{mol}\). If the frequency factor is \(1.0 \times 10^{12} \mathrm{~s}^{-1}\), what is \(k_{1}\) at \(298 \mathrm{~K} ?\) The equilibrium constant \(K_{c}\) for the reaction is \(9.83 \times 10^{3}\) at \(298 \mathrm{~K}\).

At \(1130^{\circ} \mathrm{C}\), the equilibrium constant \(\left(K_{\mathrm{c}}\right.\) ) for the reaction: $$2 \mathrm{H}_{2} \mathrm{~S}(g) \rightleftarrows 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g)$$ is \(2.25 \times 10^{-4} .\) If \(\left[\mathrm{H}_{2} \mathrm{~S}\right]=4.84 \times 10^{-3} \mathrm{M}\) and $$\left[\mathrm{H}_{2}\right]=1.50 \times 10^{-3} M, \text { calculate }\left[\mathrm{S}_{2}\right]$$.

Which of the following statements is correct about a reacting system at equilibrium: (a) the concentrations of reactants are equal to the concentrations of products, (b) the rate of the forward reaction is equal to the rate of the reverse reaction.

Consider the reversible reaction \(\mathrm{A} \rightleftarrows \mathrm{B}\). Explain how equilibrium can be reached by starting with only A, only \(\mathrm{B}\), or a mixture of \(\mathrm{A}\) and \(\mathrm{B}\).

What effect does an increase in pressure have on each of the following systems at equilibrium? The temperature is kept constant, and, in each case, the reactants are in a cylinder fitted with a movable piston. (a) \(\mathrm{A}(s) \rightleftarrows 2 \mathrm{~B}(s)\) (b) \(2 \mathrm{~A}(l) \rightleftarrows \mathrm{B}(l)\) (c) \(\mathrm{A}(s) \rightleftarrows \mathrm{B}(g)\) (d) \(\mathrm{A}(g) \rightleftarrows \mathrm{B}(g)\) (e) \(\mathrm{A}(g) \rightleftarrows 2 \mathrm{~B}(g)\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free