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Briefly comment on the effect of a catalyst on each of the following: (a) activation energy, (b) reaction mechanism, (c) enthalpy of reaction, (d) rate of forward reaction, (e) rate of reverse reaction.

Short Answer

Expert verified
A catalyst lowers activation energy, changes the mechanism, keeps enthalpy constant, and increases both reaction rates.

Step by step solution

01

Understanding Activation Energy

A catalyst provides an alternative pathway with a lower activation energy for a reaction. This means that less energy is required for the reactants to transform into products, allowing the reaction to proceed more quickly under the same conditions.
02

Exploring Reaction Mechanism

A catalyst can change the reaction mechanism by introducing a different route for the reaction. This new route usually involves different intermediate species and transition states. However, the starting materials and final products remain the same.
03

Enthalpy of Reaction Unchanged

The enthalpy change (\( \Delta H \) of the reaction remains unchanged when a catalyst is used because the catalyst does not alter the energetics of the reactants or products, only the pathway between them.
04

Increasing Rate of Forward Reaction

By reducing the activation energy, a catalyst increases the rate of the forward reaction. More reactant molecules have sufficient energy to overcome the lower energy barrier, leading to an increased reaction rate.
05

Increasing Rate of Reverse Reaction

Similarly, for the reverse reaction, the catalyst also lowers the activation energy and increases the rate. Catalysts do not favor one direction of the reaction over the other; they accelerate both the forward and reverse reactions equally by lowering the energy barriers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Activation Energy
Activation energy is the minimum amount of energy required for a chemical reaction to occur. Imagine this as the energy barrier that reactants need to overcome to transform into products.
With the addition of a catalyst, this barrier is lowered. Catalysts provide an alternative route with reduced activation energy, making it easier for reactants to proceed. This means the reaction can happen faster and more efficiently.
  • Lower activation energy means more molecules can participate in the reaction.
  • This results in a higher reaction rate without the need for increased temperature or pressure.
Understanding how a catalyst affects activation energy is crucial in chemistry, as it enables the optimization of reaction conditions.
Reaction Mechanism
The reaction mechanism is the step-by-step process by which reactants convert to products. It involves a series of elementary steps, each with its own transition state.
A catalyst can change this mechanism by introducing a new pathway. While the initial and final substances are the same, the intermediates and transition states might differ.
  • Catalysts often create more stable intermediate stages.
  • This new mechanism helps lower the activation energy.
By altering the mechanism, catalysts can significantly speed up reactions, making industrial and laboratory processes more efficient.
Enthalpy of Reaction
The enthalpy of reaction (\( \Delta H \)) represents the heat change during a chemical reaction. It's the difference in energy between reactants and products.
Importantly, the use of a catalyst does not affect this enthalpy change. Catalysts speed up the reaction by altering the transition pathway, but they do not change the overall energy balance.
  • Enthalpy remains constant because reactants and products are the same.
  • Catalysts affect only the rate, not the energy released or absorbed.
This means that while a catalyst makes the reaction faster, it doesn't make it more or less energy-efficient.
Reaction Rate
The reaction rate is how quickly reactants turn into products in a given time period. Catalysts play a crucial role by enhancing this speed.
By lowering the activation energy, more reactant molecules can surpass the energy barrier. This increases the rate of both the forward and reverse reactions.
  • Catalysts equally speed up both directions of a reversible reaction.
  • This balanced effect helps in reaching equilibrium faster without favoring either side.
Overall, catalysts are invaluable for increasing the efficiency of chemical processes, saving both time and resources.

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Most popular questions from this chapter

The concentrations of enzymes in cells are usually quite small. What is the biological significance of this fact?

Chlorine oxide \((\mathrm{ClO}),\) which plays an important role in the depletion of ozone, decays rapidly at room temperature according to the equation: $$ 2 \mathrm{ClO}(g) \longrightarrow \mathrm{Cl}_{2}(g)+\mathrm{O}_{2}(g) $$ From the following data, determine the reaction order and calculate the rate constant of the reaction. $$ \begin{array}{ll} \text { Time (s) } & {[\mathrm{ClO}](M)} \\ \hline 0.12 \times 10^{-3} & 8.49 \times 10^{-6} \\ 0.96 \times 10^{-3} & 7.10 \times 10^{-6} \\ 2.24 \times 10^{-3} & 5.79 \times 10^{-6} \\ 3.20 \times 10^{-3} & 5.20 \times 10^{-6} \\ 4.00 \times 10^{-3} & 4.77 \times 10^{-6} \end{array} $$

A protein molecule \(\mathrm{P}\) of molar mass \(\mathscr{M}\) dimerizes when it is allowed to stand in solution at room temperature. A plausible mechanism is that the protein molecule is first denatured (i.e., loses its activity due to a change in overall structure) before it dimerizes: \(\mathrm{P} \stackrel{k}{\longrightarrow} \mathrm{P}^{*}(\) denatured \() \quad\) (slow) $$ 2 \mathrm{P}^{*} \longrightarrow \mathrm{P}_{2} $$ (fast) where the asterisk denotes a denatured protein molecule. Derive an expression for the average molar mass (of \(\mathrm{P}\) and \(\left.\mathrm{P}_{2}\right), \bar{U},\) in terms of the initial protein concentration \([\mathrm{P}]_{0}\) and the concentration at time \(t,[\mathrm{P}]_{t},\) and \(\mathscr{M} .\) Describe how you would determine \(k\) from molar mass measurements.

The reaction \(\mathrm{S}_{2} \mathrm{O}_{8}^{2-}+2 \mathrm{I}^{-} \longrightarrow 2 \mathrm{SO}_{4}^{2-}+\mathrm{I}_{2}\) proceeds slowly in aqueous solution, but it can be catalyzed by the \(\mathrm{Fe}^{3+}\) ion. Given that \(\mathrm{Fe}^{3+}\) can oxidize \(\mathrm{I}^{-}\) and \(\mathrm{Fe}^{2+}\) can reduce \(\mathrm{S}_{2} \mathrm{O}_{8}^{2-},\) write a plausible two-step mechanism for this reaction. Explain why the uncatalyzed reaction is slow.

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