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The first-order rate constant for the dehydration of carbonic acid: $$ \mathrm{H}_{2} \mathrm{CO}_{3} \longrightarrow \mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} $$ is about \(1 \times 10^{2} \mathrm{~s}^{-1}\). In view of this rather high rate constant, explain why it is necessary to have the enzyme carbonic anhydrase to enhance the rate of dehydration in the lungs.

Short Answer

Expert verified
Carbonic anhydrase accelerates CO2 removal, matching physiological demands despite a high intrinsic rate.

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01

Understand the Chemical Reaction

The dehydration of carbonic acid is a chemical reaction where carbonic acid (\(\mathrm{H}_{2} \mathrm{CO}_{3}\)) splits into carbon dioxide (\(\mathrm{CO}_{2}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)). The transformation can be represented as: \[\mathrm{H}_{2} \mathrm{CO}_{3} \rightarrow \mathrm{CO}_{2} + \mathrm{H}_{2} \mathrm{O}.\] This process is significant in various biological systems, particularly in the context of respiration.
02

Analyze the Role of the Rate Constant

The first-order rate constant \(k\) for this reaction is given as \(1 \times 10^{2} \, \mathrm{s}^{-1}\). This indicates that the reaction proceeds at a relatively fast pace under normal conditions due to the high value of \(k\). First-order reactions have rate laws of the form \(\text{Rate} = k[\text{Reactant}]\), thus, suggesting the reaction does not necessitate catalysis under basic chemical conditions.
03

Examine Biological Relevance in the Lungs

In biological systems, such as the human lungs, rapid elimination of \(\mathrm{CO}_{2}\) formed is crucial for maintaining proper gas exchange and systemic pH balance. Despite a high rate constant under chemical conditions, physiological reactions may demand even greater speed to meet biological needs. This situation arises because living systems operate under different constraints than simple chemical reactions, such as the need to quickly expel CO2 initially dissolved in blood.
04

Discuss the Role of Carbonic Anhydrase

Carbonic anhydrase is the enzyme that catalyzes the hydration and dehydration of carbonic acid in the blood, enhancing the reaction rate beyond the capability of the intrinsic rate constant alone. Although the rate constant is high, the enzyme ensures the reaction proceeds at optimal physiological rates necessary for efficient respiratory function, facilitating rapid removal of carbon dioxide from the bloodstream into lung air spaces.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dehydration of Carbonic Acid
Dehydration of carbonic acid is a chemical process where carbonic acid (\(\mathrm{H}_{2} \mathrm{CO}_{3}\)) breaks down into carbon dioxide (\(\mathrm{CO}_{2}\)) and water (\(\mathrm{H}_{2}\mathrm{O}\)). This reaction plays a crucial role in our body's respiratory system, especially in the lungs.
  • The chemical equation is: \(\mathrm{H}_{2} \mathrm{CO}_{3} \rightarrow \mathrm{CO}_{2} + \mathrm{H}_{2} \mathrm{O}\).
  • This transformation helps in expelling \(\mathrm{CO}_{2}\), a waste product, from our body.
  • The reaction naturally occurs quite fast, with a rate constant indicating a speedy process even without extra help.
However, despite this inherent speed, our body sometimes needs it to be even faster, especially during vigorous activities. That’s where enzyme catalysis steps in.
Reaction Rate Constant
A reaction rate constant is a numerical value that provides insight into how fast a particular reaction occurs. For the dehydration of carbonic acid, this rate constant is quite high, at \(1 \times 10^{2} \, \mathrm{s}^{-1}\).
  • This means the reaction is fast under normal conditions.
  • A high rate constant like this suggests that plenty of carbon dioxide is naturally being produced and released.
In the context of this reaction, the term "first-order" is important. It implies that the reaction speed is directly proportional to the concentration of the carbonic acid. Despite the fast natural speed, the biological process demands even more rapid rates for efficient gas exchange in the body.
Enzyme Catalysis
Enzyme catalysis is the acceleration of chemical reactions by enzymes. In our bodies, enzymes serve as incredible natural catalysts. One such enzyme is carbonic anhydrase, which plays a crucial role in speeding up the dehydration of carbonic acid.
  • This enzyme enhances the reaction rate much further than the intrinsic rate constant would allow.
  • It ensures efficient functioning of respiratory processes by processing reactions faster than they'd proceed under typical conditions.
Thanks to carbonic anhydrase, the chemical conversion necessary for breathing happens swiftly, supporting vital physiological functions and maintaining balance in the bloodstream.
Gas Exchange
Gas exchange in the lungs involves swapping of \(\mathrm{O}_{2}\) (oxygen) and \(\mathrm{CO}_{2}\) (carbon dioxide) between the bloodstream and the air we breathe.
  • This process helps to deliver oxygen to cells for energy production while removing \(\mathrm{CO}_{2}\), a by-product of cellular respiration.
  • Efficiency in gas exchange is critical to maintain life-sustaining processes.
Fast and effective removal of \(\mathrm{CO}_{2}\) is important to ensure our body functions smoothly, explaining why enzymes like carbonic anhydrase are so important. They make this crucial conversion process ultrafast, thus, supporting the respiratory system's needs at all times.
Respiratory System
The respiratory system is integral to our survival, responsible for taking in oxygen and expelling carbon dioxide from the body. It consists of organs such as the lungs and airways, which collaborate to ensure effective breathing.
  • Carbonic anhydrase assists the respiratory system by accelerating the conversion of carbon dioxide, enabling quicker release from the bloodstream into the lungs.
  • This efficient processing means that your body can handle different activity levels without problems related to \(\mathrm{CO}_{2}\) buildup.
Without such enzymatic boosts, maintaining the balance of gases during everyday activities or intense exercise would be far less efficient. Thus, carbonic anhydrase plays a vital role in keeping our respiratory systems running smoothly and effectively.

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Most popular questions from this chapter

Many reactions involving heterogeneous catalysts are zeroth order; that is, rate \(=k\). An example is the decomposition of phosphine \(\left(\mathrm{PH}_{3}\right)\) over tungsten \((\mathrm{W})\) $$ 4 \mathrm{PH}_{3}(g) \longrightarrow \mathrm{P}_{4}(g)+6 \mathrm{H}_{2}(g) $$ It is found that the reaction is independent of \(\left[\mathrm{PH}_{3}\right]\) as long as phosphine's pressure is sufficiently high \((\geq 1\) atm \()\). Explain.

To carry out metabolism, oxygen is taken up by hemoglobin \((\mathrm{Hb})\) to form oxyhemoglobin \(\left(\mathrm{Hb} \mathrm{O}_{2}\right)\) according to the simplified equation: $$ \mathrm{Hb}(a q)+\mathrm{O}_{2}(a q) \stackrel{k}{\longrightarrow} \mathrm{HbO}_{2}(a q) $$ where the second-order rate constant is \(2.1 \times 10^{6} / M \cdot \mathrm{s}\) at \(37^{\circ} \mathrm{C}\). For an average adult, the concentrations of \(\mathrm{Hb}\) and \(\mathrm{O}_{2}\) in the blood at the lungs are \(8.0 \times 10^{-6} \mathrm{M}\) and \(1.5 \times 10^{-6} M,\) respectively. (a) Calculate the rate of formation of \(\mathrm{HbO}_{2}\). (b) Calculate the rate of consumption of \(\mathrm{O}_{2}\). (c) The rate of formation of \(\mathrm{HbO}_{2}\) increases to \(1.4 \times 10^{-4} M / \mathrm{s}\) during exercise to meet the demand of the increased metabolism rate. Assuming the \(\mathrm{Hb}\) concentration to remain the same, what must the oxygen concentration be to sustain this rate of \(\mathrm{HbO}_{2}\) formation?

The rate law for the reaction: $$ \mathrm{NH}_{4}^{+}(a q)+\mathrm{NO}_{2}^{-}(a q) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) $$ is given by rate \(=k\left[\mathrm{NH}_{4}^{+}\right]\left[\mathrm{NO}_{2}^{-}\right]\). At \(25^{\circ} \mathrm{C},\) the rate constant is \(3.0 \times 10^{-4} / M \cdot \mathrm{s} .\) Calculate the rate of the reaction at this temperature if \(\left[\mathrm{NH}_{4}^{+}\right]=0.36 M\) and \(\left[\mathrm{NO}_{2}^{-}\right]=0.075 \mathrm{M}\).

"The rate constant for the reaction: $$ \mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g) $$ is \(1.64 \times 10^{-6} / M \cdot \mathrm{s} . "\) What is incomplete about this statement?

Thallium(I) is oxidized by cerium(IV) as follows: $$ \mathrm{Tl}^{+}+2 \mathrm{Ce}^{4+} \longrightarrow \mathrm{Tl}^{3+}+2 \mathrm{Ce}^{3+} $$ The elementary steps, in the presence of \(\mathrm{Mn}(\mathrm{II}),\) are as follows: $$ \begin{aligned} \mathrm{Ce}^{4+}+\mathrm{Mn}^{2+} & \mathrm{Ce}^{3+}+\mathrm{Mn}^{3+} \\ \mathrm{Ce}^{4+}+\mathrm{Mn}^{3+} & \longrightarrow \mathrm{Ce}^{3+}+\mathrm{Mn}^{4+} \\ \mathrm{Tl}^{+}+\mathrm{Mn}^{4+} \longrightarrow & \mathrm{Tl}^{3+}+\mathrm{Mn}^{2+} \end{aligned} $$ (a) Identify the catalyst, intermediates, and the ratedetermining step if the rate law is rate \(=k\left[\mathrm{Ce}^{4+}\right]\left[\mathrm{Mn}^{2+}\right]\) (b) Explain why the reaction is slow without the catalyst. (c) Classify the type of catalysis (homogeneous or heterogeneous).

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