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What are the characteristics of a catalyst?

Short Answer

Expert verified
Catalysts increase reaction rate, lower activation energy, remain unchanged, are reusable, and can be selective.

Step by step solution

01

Understanding Catalysts

A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Catalysts are crucial in both biological processes and industrial applications.
02

Analyzing the Primary Function

The primary function of a catalyst is to lower the activation energy required for a reaction. By providing an alternative pathway for the reaction that has a lower energy barrier, catalysts allow the reaction to proceed faster.
03

Examining Chemical Stability

Catalysts are not consumed or altered permanently during the reaction process. They may engage in intermediate chemical interactions, but they are regenerated in their original form by the end of the reaction.
04

Exploring Reusability

Because catalysts are not consumed in the reaction, they can be used repeatedly. This makes them efficient and cost-effective, especially in industrial processes where reactions are conducted on a large scale.
05

Identifying Selective Characteristics

Catalysts can be highly selective, affecting only specific reactions or particular types of reactions. This selectivity is useful in synthesizing desired products and avoiding unwanted by-products.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Activation Energy
Catalysts are like keys that unlock the energy gates in chemical reactions. They significantly lower the activation energy, or the initial energy barrier that reactants need to overcome to transform into products. Activation energy is the minimum energy required to initiate a chemical reaction. By providing an easier and alternative path, catalysts speed up reactions while remaining unchanged themselves.
- Imagine pushing a heavy boulder up a steep hill without help. The hill represents high activation energy. - Introduce a ramp—your catalyst—that makes the climb easier and faster.
This is how catalysts lower activation energy, facilitating quicker reactions. The reaction takes less energy and occurs more rapidly.
Chemical Stability
Despite participating actively in chemical reactions, catalysts offer remarkable chemical stability. They are not permanently changed or consumed during the process. Instead, they might participate in temporary interactions, but they always return to their original state by the reaction's end.
- Think of a friend helping out during a group project but not taking any of the materials home. Your friend’s contribution makes the process smoother, but they leave exactly as they started.
Catalysts may form temporary bonds or intermediates but emerge from the reaction just as they entered—stable and unaltered. This stability is crucial for their function and effectiveness in multiple reactions.
Reusability
A key benefit of catalysts is their reusability. Since they are not consumed in chemical reactions, they can be used multiple times. This capability makes them incredibly efficient and cost-effective, especially in industrial processes that involve continual and large-scale reactions.
- Picture a tool that never wears out no matter how many times you use it---the ideal scenario in any workshop. - Because catalysts don’t get used up, they save energy and resources, limiting the need for constant replacements.
Their reuse in consecutive reactions without loss of efficiency is both an ecological and economic advantage, supporting sustainable practices.
Selective Characteristics
Catalysts can be extremely selective, influencing only specific reactions or certain pathways. This property is crucial when precision is needed, such as in industrial settings where desired outcomes help avoid unwanted by-products.
- Similar to a detective finding the culprit by following only particular evidence, catalysts focus solely on specific reaction routes. - This selectivity ensures that reactions yield the right products while minimizing errors or by-products.
Such precision is beneficial in synthesizing pharmaceuticals, foods, and other vital chemicals where exact reactions are paramount.

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Most popular questions from this chapter

Polyethylene is used in many items, including water pipes, bottles, electrical insulation, toys, and mailer envelopes. It is a polymer, a molecule with a very high molar mass made by joining many ethylene molecules together. (Ethylene is the basic unit, or monomer, for polyethylene.) The initiation step is: \(\mathrm{R}_{2} \stackrel{k_{1}}{\longrightarrow} 2 \mathrm{R} \cdot\) (initiation) The \(\mathrm{R}\). species (called a radical) reacts with an ethylene molecule (M) to generate another radical: $$ \mathrm{R} \cdot+\mathrm{M} \longrightarrow \mathrm{M}_{1} $$ The reaction of \(\mathrm{M}_{1}\). with another monomer leads to the growth or propagation of the polymer chain: \(\mathrm{M}_{1} \cdot+\mathrm{M} \stackrel{k_{\mathrm{p}}}{\longrightarrow} \mathrm{M}_{2} \cdot \quad\) (propagation) This step can be repeated with hundreds of monomer units. The propagation terminates when two radicals combine: $$ \mathbf{M}^{\prime} \cdot+\mathbf{M}^{\prime \prime} \cdot \stackrel{k_{\mathrm{t}}}{\longrightarrow} \mathbf{M}^{\prime}-\mathbf{M}^{\prime \prime} \quad \text { (termination) } $$ The initiator frequently used in the polymerization of ethylene is benzoyl peroxide \(\left[\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2}\right]\) : $$ \left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2} \longrightarrow 2 \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO} $$ This is a first-order reaction. The half-life of benzoyl peroxide at \(100^{\circ} \mathrm{C}\) is \(19.8 \mathrm{~min}\). (a) Calculate the rate constant (in \(\min ^{-1}\) ) of the reaction. (b) If the half-life of benzoyl peroxide is \(7.30 \mathrm{~h}\), or \(438 \mathrm{~min}\), at \(70^{\circ} \mathrm{C},\) what is the activation energy (in \(\mathrm{kJ} / \mathrm{mol}\) ) for the decomposition of benzoyl peroxide? (c) Write the rate laws for the elementary steps in the preceding polymerization process, and identify the reactant, product, and intermediates. (d) What condition would favor the growth of long, high-molar-mass polyethylenes?

The reaction \(\mathrm{H}+\mathrm{H}_{2} \longrightarrow \mathrm{H}_{2}+\mathrm{H}\) has been studied for many years. Sketch a potential-energy versus reaction progress diagram for this reaction.

"The rate constant for the reaction: $$ \mathrm{NO}_{2}(g)+\mathrm{CO}(g) \longrightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g) $$ is \(1.64 \times 10^{-6} / M \cdot \mathrm{s} . "\) What is incomplete about this statement?

The activation energy for the reaction: $$ \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{O}(g) $$ is \(2.4 \times 10^{2} \mathrm{~kJ} / \mathrm{mol}\) at \(600 \mathrm{~K}\). Calculate the percentage of the increase in rate from \(600 \mathrm{~K}\) to \(606 \mathrm{~K}\). Comment on your results.

The rate of the reaction between \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) to form \(\mathrm{HI}\) increases with the intensity of visible light. (a) Explain why this fact supports a two-step mechanism. \(\left(\mathrm{I}_{2}\right.\) vapor is purple.) (b) Explain why the visible light has no effect on the formation of \(\mathrm{H}\) atoms.

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