Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Distinguish between average rate and instantaneous rate. Which of the two rates gives us an unambiguous measurement of reaction rate? Why?

Short Answer

Expert verified
The instantaneous rate gives an unambiguous reaction rate measurement because it is specific to a moment in time.

Step by step solution

01

Understanding Rates

Begin by understanding the two types of rates: average rate and instantaneous rate. The average rate is calculated over a finite period of time, while the instantaneous rate is the rate at a specific moment.
02

Calculating Average Rate

The average rate of a reaction can be determined by taking the change in concentration of a reactant or product divided by the time interval over which the change occurs. Mathematically it is given as: \[ \text{Average Rate} = \frac{\Delta [ ext{Concentration}]}{\Delta t} \] where \( \Delta [\text{Concentration}] \) is the change in concentration and \( \Delta t \) is the change in time.
03

Calculating Instantaneous Rate

To determine the instantaneous rate, one needs to find the derivative of the concentration with respect to time at a specific point. This involves calculus and is represented as: \[ \text{Instantaneous Rate} = \frac{d[ ext{Concentration}]}{dt} \]
04

Comparing Rates

When comparing the two, the instantaneous rate gives a specific and precise measurement of the reaction rate at a particular time point, whereas the average rate may obscure fluctuations by smoothing them over a time period.
05

Determining Unambiguous Measurement

The instantaneous rate gives an unambiguous measure of the reaction rate because it reflects the exact rate at a specific time without averaging over a time period, capturing rapid changes and precise behavior of the reaction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Rate
The average rate of a reaction provides a broad view of how fast a reaction is occurring over a certain period.
  • It is calculated by taking the change in concentration of a substance and dividing it by the time interval during which this change occurs.
  • Mathematically, it can be expressed as: \( \text{Average Rate} = \frac{\Delta [\text{Concentration}]}{\Delta t} \), where \( \Delta [\text{Concentration}] \) is the change in concentration and \( \Delta t \) represents the time interval.

A helpful analogy is thinking about a car trip. The average speed can be determined by dividing the total distance by the total time taken. Similarly, average rate tells us how overall change happens during the reaction, but may not reflect any fluctuations within the time span.
Instantaneous Rate
Instantaneous rate provides a precise measurement of how fast a reaction proceeds at a particular moment.
  • To find the instantaneous rate, you focus on a single point in time, much like checking a car's speedometer to find out how fast it's going at that very second.
  • This measurement can be found using calculus, particularly through the derivative of concentration with respect to time: \( \text{Instantaneous Rate} = \frac{d[\text{Concentration}]}{dt} \).

This method allows for capturing the most current reaction speed, reflecting immediate changes and offering a clear picture of the reaction's behavior at a specific point.
Derivative in Calculus
The derivative in calculus is a powerful tool applied in determining the instantaneous rate of reaction. It measures how a function changes at any given point and is essential for finding rates.
  • The rate at which concentration changes over a small time period can be described by the derivative \( \frac{d[\text{Concentration}]}{dt} \).
  • This mathematical concept is used to find the slope of the tangent line to the concentration vs. time graph at a specific point.

The derivative helps in pinpointing the exact rate of reaction at any given second, aiding in analyzing rapid changes and intricate details that average rate might miss.
Concentration Change
Concentration change is a fundamental aspect in calculating both average and instantaneous rates of reaction.
  • Changes in concentration of either reactants or products help determine the rate at which chemical processes occur.
  • In the context of rates, \( \Delta [\text{Concentration}] \) represents the difference in initial and final concentrations over a time period \( \Delta t \).

Understanding how concentration changes over time offers insight into the progress and speed of a reaction, allowing us to measure both short-term (instantaneous) and long-term (average) changes.
Time Interval in Reactions
The time interval in reactions is crucial for calculating an accurate reaction rate, especially for determining average rates.
  • It is symbolized by \( \Delta t \), representing the period over which a reaction’s progress is measured.
  • Smaller time intervals offer a clearer picture of fluctuations in reaction speed, especially when determining instantaneous rate.

Choosing the correct time interval is essential, as longer intervals might smooth out rapid changes, yielding average rates that may not reflect specific rate dynamics occurring at particular moments.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following elementary steps for a consecutive reaction: $$ \mathrm{A} \stackrel{k_{1}}{\longrightarrow} \mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{C} $$ (a) Write an expression for the rate of change of \(\mathrm{B}\). (b) Derive an expression for the concentration of B under "steady-state" conditions; that is, when \(\mathrm{B}\) is decomposing to \(\mathrm{C}\) at the same rate as it is formed from \(\mathrm{A}\).

The equation for the combustion of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\) is: $$ 2 \mathrm{C}_{2} \mathrm{H}_{6}(g)+7 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l) $$ Explain why it is unlikely that this equation also represents the elementary step for the reaction.

The decomposition of \(\mathrm{N}_{2} \mathrm{O}\) to \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\) is a first-order reaction. At \(730^{\circ} \mathrm{C}\) the half-life of the reaction is \(3.58 \times 10^{3}\) min. If the initial pressure of \(\mathrm{N}_{2} \mathrm{O}\) is 2.10 atm at \(730^{\circ} \mathrm{C},\) calculate the total gas pressure after one half-life. Assume that the volume remains constant.

The rate law for the reaction: $$ 2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NOCl}(g) $$ is given by rate \(=k[\mathrm{NO}]\left[\mathrm{Cl}_{2}\right]\). (a) What is the order of the reaction? (b) A mechanism involving the following steps has been proposed for the reaction: $$ \begin{aligned} \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) & \longrightarrow \mathrm{NOCl}_{2}(g) \\ \mathrm{NOCl}_{2}(g)+\mathrm{NO}(g) & \longrightarrow 2 \mathrm{NOCl}(g) \end{aligned} $$ If this mechanism is correct, what does it imply about the relative rates of these two steps?

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is \(10.0 \mathrm{~cm}^{3} .\) Calculate the surface area of the catalyst. If the sphere is broken down into eight smaller spheres, each having a volume of \(1.25 \mathrm{~cm}^{3},\) what is the total surface area of the spheres? Which of the two geometric configurations of the catalyst is more effective? (The surface area of a sphere is \(4 \pi r^{2}\), where \(r\) is the radius of the sphere.) Based on your analysis here, explain why it is sometimes dangerous to work in grain elevators.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free