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Determine the overall orders of the reactions to which the following rate laws apply: (a) rate \(=k\left[\mathrm{NO}_{2}\right]^{2},(\mathrm{~b})\) rate \(=k\), (c) rate \(=k\left[\mathrm{H}_{2}\right]^{2}\left[\mathrm{Br}_{2}\right]^{1 / 2}\) (d) rate \(=k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right]\)

Short Answer

Expert verified
(a) 2, (b) 0, (c) 2.5, (d) 3

Step by step solution

01

Understand Reaction Order

The reaction order indicates how the rate is affected by the concentration of reactants. It is the sum of the powers of the concentration terms in the rate law.
02

Analyze Rate Law for Part (a)

For rate law rate \( = k[\mathrm{NO}_{2}]^{2} \), only one reactant \( [\mathrm{NO}_{2}] \) appears with a power of 2. This means the reaction order is simply \( 2 \).
03

Analyze Rate Law for Part (b)

For rate law rate \( = k \), there are no concentration terms. This indicates a zero-order reaction, as the rate does not depend on the concentration of any reactant.
04

Analyze Rate Law for Part (c)

In the rate law rate \( = k [\mathrm{H}_{2}]^{2} [\mathrm{Br}_{2}]^{1/2} \), the order with respect to \( [\mathrm{H}_{2}] \) is 2, and with respect to \( [\mathrm{Br}_{2}] \) is \( 1/2 \). The overall reaction order is \( 2 + 1/2 = 2.5 \).
05

Analyze Rate Law for Part (d)

For rate law rate \( = k [\mathrm{NO}]^{2} [\mathrm{O}_{2}] \), the order with respect to \( [\mathrm{NO}] \) is 2 and with respect to \( [\mathrm{O}_{2}] \) is 1. The overall reaction order is \( 2 + 1 = 3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
A rate law is an equation that shows how the rate of a chemical reaction depends on the concentration of its reactants. It typically takes the form: \[ \text{rate} = k[A]^x[B]^y... \]where:
  • rate is the speed at which the reaction occurs.
  • k is the rate constant, a value that changes with temperature and different reactions.
  • [A] and [B] are the concentrations of the reactants.
  • x and y are the reaction orders with respect to each reactant.
In any given rate law, increasing the concentration of a reactant with a positive reaction order increases the rate of reaction. Each exponent in the rate law indicates how much the concentration of that reactant affects the rate.
Concentration of Reactants
The concentration of reactants is a crucial factor in chemical kinetics and determining how quickly a reaction proceeds. Concentration is typically measured in molarity (M), which represents the number of moles of a solute per liter of solution. When the concentration of reactants changes, it can significantly impact the reaction rate:
  • An increase in concentration usually leads to more frequent collisions between reactant molecules, thereby speeding up the reaction.
  • If a reactant's order is zero, changes in its concentration do not affect the overall rate.
Understanding how reactant concentration affects rate is vital in controlling reactions in industrial processes and laboratory settings.
Zero-Order Reaction
In a zero-order reaction, the rate is independent of the concentration of the reactants. This means that the rate remains constant as long as there is some amount of reactant present. A typical rate law for a zero-order reaction looks like this:\[ \text{rate} = k \]where the rate continues at a constant pace determined by k (rate constant), regardless of the concentrations of the reactants. Zero-order reactions are less common and often observed where a catalyst or specific surface area limits the reaction. They provide valuable information about processes where only catalysts or other non-concentration factors affect the rate.
Overall Reaction Order
The overall reaction order is the sum of the powers of the concentration terms in a rate law. It depicts the influence of all reactants' concentrations on the reaction rate as a whole. Calculating it involves adding up the individual orders, like so:
  • For rate law \( \text{rate} = k[\mathrm{A}]^m[\mathrm{B}]^n \), the overall reaction order is \( m+n \).
The overall reaction order helps chemists to understand complex reactions and predict how changes in reactant concentrations will affect the rate. High-order reactions tend to be sensitive to concentration changes, while low-order ones are less so. Understanding this can be critical in industries where precise reaction rates define the quality and yield of a product.

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Most popular questions from this chapter

The activation energy for the decomposition of hydrogen peroxide: $$ 2 \mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g) $$ is \(42 \mathrm{~kJ} / \mathrm{mol}\), whereas when the reaction is catalyzed by the enzyme catalase, it is \(7.0 \mathrm{~kJ} / \mathrm{mol}\). Calculate the temperature that would cause the uncatalyzed decomposition to proceed as rapidly as the enzyme-catalyzed decomposition at \(20^{\circ} \mathrm{C}\). Assume the frequency factor A to be the same in both cases.

The rate of the reaction between \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) to form \(\mathrm{HI}\) increases with the intensity of visible light. (a) Explain why this fact supports a two-step mechanism. \(\left(\mathrm{I}_{2}\right.\) vapor is purple.) (b) Explain why the visible light has no effect on the formation of \(\mathrm{H}\) atoms.

The reaction \(2 \mathrm{~A}+3 \mathrm{~B} \longrightarrow \mathrm{C}\) is first order with respect to \(\mathrm{A}\) and \(\mathrm{B}\). When the initial concentrations are \([\mathrm{A}]=1.6 \times 10^{-2} M\) and \([\mathrm{B}]=2.4 \times 10^{-3} M,\) the rate is \(4.1 \times 10^{-4} \mathrm{M} / \mathrm{s} .\) Calculate the rate constant of the reaction.

Explain what is meant by the rate law of a reaction.

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is \(10.0 \mathrm{~cm}^{3} .\) Calculate the surface area of the catalyst. If the sphere is broken down into eight smaller spheres, each having a volume of \(1.25 \mathrm{~cm}^{3},\) what is the total surface area of the spheres? Which of the two geometric configurations of the catalyst is more effective? (The surface area of a sphere is \(4 \pi r^{2}\), where \(r\) is the radius of the sphere.) Based on your analysis here, explain why it is sometimes dangerous to work in grain elevators.

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