Chapter 14: Problem 116
The activation energy for the reaction: $$ \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{O}(g) $$ is \(2.4 \times 10^{2} \mathrm{~kJ} / \mathrm{mol}\) at \(600 \mathrm{~K}\). Calculate the percentage of the increase in rate from \(600 \mathrm{~K}\) to \(606 \mathrm{~K}\). Comment on your results.
Short Answer
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Key Concepts
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