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Explain what is meant by the order of a reaction.

Short Answer

Expert verified
The order of a reaction describes how the reaction rate depends on reactant concentrations and indicates the reaction mechanism.

Step by step solution

01

Understand the Concept of Reaction Order

The order of a reaction refers to the power to which the concentration of a reactant is raised in the rate law equation. It indicates how the reaction rate is affected by the concentration of a reactant.
02

Write the Rate Law Expression

For a general reaction \( aA + bB \rightarrow C \), the rate law can be expressed as: \[ \text{Rate} = k[A]^m[B]^n \] where \( k \) is the rate constant, \( [A] \) and \( [B] \) are the concentrations of reactants \( A \) and \( B \), and \( m \) and \( n \) are their respective orders.
03

Determine Overall Reaction Order

The overall order of the reaction is the sum of the exponents in the rate law expression. For instance, if the rate law is \( ext{Rate} = k[A]^2[B]^1 \), the overall order is \( 2 + 1 = 3 \).
04

Interpretation and Significance

The order of each reactant indicates how changes in its concentration affect the reaction rate. For example, if \( m = 1 \), doubling \( [A] \) doubles the rate; if \( m = 2 \), doubling \( [A] \) quadruples the rate. The overall order gives insight into the reaction mechanism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law Expression
A rate law expression is a mathematical equation used to describe how the rate of a chemical reaction depends on the concentrations of its reactants. For a reaction such as \( aA + bB \rightarrow C \), the rate law can be written as:
  • \( \text{Rate} = k[A]^m[B]^n \)
Here, \( k \) is the rate constant which we'll discuss later, \([A]\) and \([B]\) represent the molar concentrations of reactants \( A \) and \( B \), and \( m \) and \( n \) are the reaction orders with respect to \( A \) and \( B \) respectively. The exponent values \( m \) and \( n \) are determined experimentally and indicate how sensitive the rate is to changes in concentration. For example, if \( m = 1 \), the rate is directly proportional to the concentration of \( A \). If \( m = 2 \), the rate is proportional to the square of the concentration of \( A \). Understanding the rate law is crucial for predicting how a reaction will proceed under different conditions.
Rate Constant
The rate constant, designated by \( k \), is a unique number that relates the concentrations of reactants to the rate of reaction in the rate law expression. It is crucial as it helps dictate how fast or slow a reaction occurs. The units of \( k \) vary depending on the overall order of the reaction. For a first-order reaction, it has units of \( \text{s}^{-1} \), whereas for a second-order reaction, the units are \( \text{M}^{-1}\text{s}^{-1} \). The rate constant is influenced by factors such as temperature and the presence of a catalyst, where increasing the temperature typically increases the value of \( k \), hence increasing the reaction rate. A higher rate constant indicates a faster reaction rate under given conditions. Typically, the value of \( k \) is determined through experimental data and can provide insights into the energy required to achieve the reaction.
Reaction Mechanism
The reaction mechanism provides a step-by-step sequence of elementary reactions by which overall chemical change occurs. Each step is characterized by its own rate law expression, and the mechanism reveals the pathway from reactants to products. Understanding the mechanism is essential as it allows chemists to deduce how the reaction proceeds on a molecular level and which factors are influencing its rate. These pathways can include intermediate species and transition states, providing a deeper comprehension beyond the overall balanced equation. The reaction mechanism often adds insight into the reaction order, as it suggests which reactants or intermediates affect the rate-determining step, the slowest step in the sequence, thus impacting the overall reaction rate. The knowledge of mechanisms is vital in fields like catalysis and drug design, where knowing the intermediate stages can lead to improved processes or products.
Concentration Effect
The concentration effect in the context of reaction rates refers to how changes in the concentrations of reactants influence the speed of the reaction. According to the rate law expression, changes in reactant concentration can exponentially affect the reaction rate depending on the reaction order. For example, if a reaction is first order with respect to reactant \( A \), doubling the concentration of \( A \) will double the reaction rate. If the reaction is second order with respect to \( A \), doubling \([A]\) will quadruple the rate. This response can be directly observed in kinetic studies where the alteration in concentration is correlated with time taken for the reaction to occur. Understanding the concentration effect is essential for controlling reaction rates in industrial processes, allowing for optimization of conditions to maximize efficiency and yield in chemical production and synthesis.

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Most popular questions from this chapter

A gas mixture containing \(\mathrm{CH}_{3}\) fragments, \(\mathrm{C}_{2} \mathrm{H}_{6}\) molecules, and an inert gas (He) was prepared at \(600 \mathrm{~K}\) with a total pressure of 5.42 atm. The elementary reaction $$ \mathrm{CH}_{3}+\mathrm{C}_{2} \mathrm{H}_{6} \longrightarrow \mathrm{CH}_{4}+\mathrm{C}_{2} \mathrm{H}_{5} $$ has a second-order rate constant of \(3.0 \times 10^{4} / M \cdot \mathrm{s} .\) Given that the mole fractions of \(\mathrm{CH}_{3}\) and \(\mathrm{C}_{2} \mathrm{H}_{6}\) are 0.00093 and 0.00077 , respectively, calculate the initial rate of the reaction at this temperature.

Consider the reaction: $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) $$ Suppose that at a particular moment during the reaction molecular hydrogen is reacting at the rate of \(0.082 \mathrm{M} / \mathrm{s}\). (a) At what rate is ammonia being formed? (b) At what rate is molecular nitrogen reacting?

The rate of the reaction between \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) to form \(\mathrm{HI}\) increases with the intensity of visible light. (a) Explain why this fact supports a two-step mechanism. \(\left(\mathrm{I}_{2}\right.\) vapor is purple.) (b) Explain why the visible light has no effect on the formation of \(\mathrm{H}\) atoms.

The rate constant for the second-order reaction: $$ 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) $$ is \(0.54 / M \cdot \mathrm{s}\) at \(300^{\circ} \mathrm{C}\). How long (in seconds) would it take for the concentration of \(\mathrm{NO}_{2}\) to decrease from \(0.65 M\) to \(0.18 M ?\)

Strontium-90, a radioactive isotope, is a major product of an atomic bomb explosion. It has a half-life of 28.1 yr. (a) Calculate the first-order rate constant for the nuclear decay. (b) Calculate the fraction of \({ }^{90}\) Sr that remains after 10 half-lives. (c) Calculate the number of years required for 99.0 percent of \({ }^{90} \mathrm{Sr}\) to disappear.

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