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A solution of \(6.85 \mathrm{~g}\) of a carbohydrate in \(100.0 \mathrm{~g}\) of water has a density of \(1.024 \mathrm{~g} / \mathrm{mL}\) and an osmotic pressure of 4.61 atm at \(20.0^{\circ} \mathrm{C}\). Calculate the molar mass of the carbohydrate.

Short Answer

Expert verified
The molar mass of the carbohydrate is approximately 342 g/mol.

Step by step solution

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01

Understand the formula for osmotic pressure

Osmotic pressure (\( \Pi \)) is given by the formula:\[\Pi = iMRT\]where \(i\) is the Van't Hoff factor, \(M\) is molarity in moles per liter, \(R\) is the ideal gas constant \(0.0821\, \text{L atm mol}^{-1} \text{K}^{-1}\), and \(T\) is the temperature in Kelvin.For carbohydrates, \(i = 1\) because they do not ionize in solution.
02

Convert temperature to Kelvin

Convert the given temperature from Celsius to Kelvin by adding 273.15.\[T = 20.0 + 273.15 = 293.15 \, \text{K}\]
03

Calculate molarity of the solution

First, calculate the volume of the solution using its mass and density. The total mass of the solution is \(6.85 + 100.0 = 106.85\, \text{g}\). Using the formula for density \(\rho = \text{mass/volume}\), solve for volume:\[\text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{106.85\, \text{g}}{1.024\, \text{g/mL}} = 104.32\, \text{mL} = 0.10432\, \text{L}\]Molarity (\(M\)) is the number of moles of solute per liter of solution, calculated as follows:\[M = \frac{x}{0.10432} \] where \(x\) is moles of the carbohydrate.
04

Relate osmotic pressure to molarity and calculate moles

Given \(\Pi = 4.61 \text{ atm}\), use the formula from step 1:\[4.61 = 1 \cdot M \cdot 0.0821 \cdot 293.15\]Solving for \(M\),\[M = \frac{4.61}{0.0821 \times 293.15} = 0.192\, \text{mol/L}\]The moles of carbohydrate (\(x\)) can be calculated using the molarity:\[ x = 0.192 \times 0.10432 = 0.02003 \text{ mol} \]
05

Calculate molar mass

Molar mass is given by the mass of the solute divided by the number of moles of the solute:\[\text{Molar mass} = \frac{6.85\, \text{g}}{0.02003\, \text{mol}} \approx 342\, \text{g/mol}\]

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Osmotic Pressure
Osmotic pressure is a key concept in chemistry that deals with the pressure required to stop osmosis, which is the movement of a solvent across a semipermeable membrane. It is especially useful for determining molecular weights of solutes, such as carbohydrates, dissolved in a solvent.
The formula for osmotic pressure (\( \Pi \)) is:\[\Pi = iMRT\]where:
  • \(i\) is the Van't Hoff factor, which equals 1 for non-ionizing solutes like carbohydrates.
  • \(M\) is the molarity of the solution.
  • \(R\) is the ideal gas constant.
  • \(T\) is the temperature in Kelvin.
Understanding osmotic pressure helps in calculating the concentration of the solution, giving insights into the properties of the solute in different conditions.
Ideal Gas Constant
The ideal gas constant \(R\) is a fundamental constant used in numerous equations, connecting various physical properties of substances. It plays a crucial role in the ideal gas law and formulas related to solutions. For osmotic pressure calculations, \(R\) is expressed in units of \(0.0821 \, \text{L atm mol}^{-1} \text{K}^{-1}\).
Choosing the right units for \(R\) ensures compatibility with the other measurements in the equation, like temperature in Kelvin, pressure in atm, and volume in liters. This consistency is vital for accurate measurements and calculations in chemistry and physics.
Molarity Calculation
Molarity (\(M\)) is a measure of the concentration of a solute in a solution, represented in moles of solute per liter of solution. It is calculated by dividing the number of moles of a solute (\(x\)) by the volume of the solution in liters.
In the provided exercise, the calculation of molarity involves not just the solute but understanding the total mass and resulting volume of the solution:
  • Calculate the total mass by adding solute and solvent masses.
  • Convert this mass into volume using the solution's density.
  • Determine molarity using the formula \(M = \frac{x}{{\text{volume in Liters}}}\).
This multiple-step approach ensures an accurate understanding of the concentration, crucial for further calculations like molar mass.
Density and Volume Relationship
Density is an important property that connects the mass and volume of a substance. For solutions, density (\(\rho\)) is used to find the volume of a given mass using the formula:\[\text{Volume} = \frac{\text{Mass}}{\text{Density}}\]This relationship is especially important when converting mass measurements into volume, as in the case of our carbohydrate solution.
The total mass of the solution is determined and then divided by its density to achieve precise volume calculations. This step is essential for converting measurements to the appropriate units for further calculations, such as molarity or osmotic pressure.
Temperature Conversion
Converting temperature from Celsius to Kelvin is essential when dealing with scientific equations such as the one for osmotic pressure. The conversion is straightforward: simply add 273.15 to the Celsius temperature.
For the exercise at hand, \(20.0^{\circ} \text{C}\) was converted to:
  • \(20.0 + 273.15 = 293.15 \, \text{K}\)
The Kelvin scale is preferred in scientific calculations because it starts from absolute zero, providing consistency and accuracy for formulas involving thermal dynamics and physical chemistry.

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Most popular questions from this chapter

The blood sugar (glucose) level of a diabetic patient is approximately \(0.140 \mathrm{~g}\) of glucose \(/ 100 \mathrm{~mL}\) of blood. Every time the patient ingests \(40 \mathrm{~g}\) of glucose, her blood glucose level rises to approximately \(0.240 \mathrm{~g} / 100 \mathrm{~mL}\) of blood. Calculate the number of moles of glucose per milliliter of blood and the total number of moles and grams of glucose in the blood before and after consumption of glucose. (Assume that the total volume of blood in her body is \(5.0 \mathrm{~L}\).

For ideal solutions, the volumes are additive. This means that if \(5 \mathrm{~mL}\) of \(\mathrm{A}\) and \(5 \mathrm{~mL}\) of \(\mathrm{B}\) form an ideal solution, the volume of the solution is \(10 \mathrm{~mL}\). Provide a molecular interpretation for this observation. When 500 \(\mathrm{mL}\) of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) is mixed with \(500 \mathrm{~mL}\) of water, the final volume is less than 1000 mL. Why?

Describe how you would use the osmotic pressure to determine the percent ionization of a weak, monoprotic acid.

The alcohol content of hard liquor is normally given in terms of the "proof," which is defined as twice the percentage by volume of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) present. Calculate the number of grams of alcohol present in 1.00 \(\mathrm{L}\) of 75 -proof gin. The density of ethanol is \(0.798 \mathrm{~g} / \mathrm{mL}\).

What is Henry's law? Define each term in the equation, and give its units. How would you account for the law in terms of the kinetic molecular theory of gases? Give two exceptions to Henry's law.

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