Chapter 13: Problem 83
Describe how you would use the osmotic pressure to determine the percent ionization of a weak, monoprotic acid.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Percent Ionization
Once you have the degree of ionization, the percent ionization can be obtained by multiplying the degree of ionization by 100. This changes the decimal form to a percentage, providing a clearer perspective on how much of the acid has been ionized.
- The formula used is: \[ ext{percent ionization} = ( ext{degree of ionization} imes 100)\]
Van't Hoff Factor
The van't Hoff factor is crucial when calculating osmotic pressure because it adjusts the molarity to reflect the true number of particles in the solution.
- In the case of a weak, monoprotic acid, the relationship is given by:\[ i = 1 + ext{degree of ionization} \]
- This recognizes that for each acid molecule, an additional particle results from ionization.
Degree of Ionization
You can calculate the degree of ionization from the van’t Hoff factor with:\[ ext{degree of ionization} = i - 1 \]where \( i \) is derived from the osmotic pressure equation.
- This difference captures how much ionization occurs above what would happen in a completely non-dissociating substance.
- The degree provides insight into the acid's behavior in different solution conditions, affecting reactions and equilibria.
Semipermeable Membrane
In the context of osmotic pressure, the semipermeable membrane separates two solutions and permits the passage of solvent but not solute, creating a pressure difference due to the solute concentration.
- It's this barrier that helps measure osmotic pressure by stopping the flow of water into a solution once equilibrium with external pressure is achieved.
- In lab settings, this concept is harnessed using devices like osmometers to measure how much pressure is needed to counterbalance the inward flow of water.