Chapter 13: Problem 71
The osmotic pressure of \(0.010-M\) solutions of \(\mathrm{CaCl}_{2}\) and urea at \(25^{\circ} \mathrm{C}\) are 0.605 and 0.245 atm, respectively. Calculate the van't Hoff factor for the \(\mathrm{CaCl}_{2}\) solution.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Osmotic Pressure
Osmotic pressure is calculated using the formula: \( \Pi = i \cdot M \cdot R \cdot T \). Here:
- \( i \) is the van’t Hoff factor, accounting for the degree of ionization of the solute.
- \( M \) is the molarity of the solution, representing concentration.
- \( R \) is the ideal gas constant (0.0821 \( L \, atm \, K^{-1} \, mol^{-1} \)).
- \( T \) is the temperature in Kelvin.
Molarity
- \( n \) = number of moles of solute,
- \( V \) = volume of the solution in liters.
In the context of osmotic pressure, molarity is used to determine how much solute is present, affecting how the solution behaves when a semipermeable membrane is involved.
Ideal Gas Constant
The value of \( R \) is 0.0821 \( L \, atm \, K^{-1} \, mol^{-1} \), which is derived from the properties of gases under standard conditions. The constant's universality makes it useful across different scenarios, from explaining gas behavior to predicting changes in gas properties with temperature or volume.
It's crucial in the osmotic pressure equation, linking chemical processes with broader physical principles, and allowing the interaction between gas laws and solutions.
Electrolyte Dissociation
CaCl2 is a common example of an electrolyte. It dissociates into Ca2+ and 2 Cl- ions in solution. The extent of dissociation impacts the van’t Hoff factor, which influences osmotic pressure by increasing the number of particles in a solution.
- For a compound like urea, which does not dissociate, \( i \) is typically 1.
- In contrast, dissociation increases \( i \) for an electrolyte, affecting both the boiling point elevation and freezing point depression of solutions.