Chapter 13: Problem 48
Use a phase diagram to show the difference in freezing points and boiling points between an aqueous urea solution and pure water.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Freezing Point Depression
A direct consequence is that more energy (in the form of a lower temperature) is needed to overcome these disturbances and allow the substance to solidify. The extent of freezing point depression can be calculated using the formula: \[ \Delta T_f = i \cdot K_f \cdot m \]where:
- \(\Delta T_f\) is the freezing point depression.
- \(i\) is the van 't Hoff factor (1 for urea, since it does not dissociate).
- \(K_f\) is the cryoscopic constant of the solvent water.
- \(m\) is the molality of the solution.
Boiling Point Elevation
The reason behind this is that the presence of solute particles in the liquid phase hinders the escape of solvent molecules, therefore requiring more heat to reach the point where vapor pressure equals atmospheric pressure. This phenomenon is quantitatively expressed with the following equation: \[ \Delta T_b = i \cdot K_b \cdot m \]where:
- \(\Delta T_b\) is the boiling point elevation.
- \(i\) is the van 't Hoff factor.
- \(K_b\) is the ebullioscopic constant of the solvent water.
- \(m\) is the molality of the solution.
Aqueous Solution
In the context of urea solute, the urea is the solute, and water is the solvent in the aqueous solution. The behavior of this solution can be influenced by the interactions between urea molecules and water, which impact properties such as boiling point and freezing point. Understanding how urea interacts with water on a molecular level is fundamental to grasping the modifications in its physical properties. Aqueous solutions are commonplace in biological systems and are essential for life, given that many physiological processes happen in such a medium.
Urea Solute
This non-dissociative behavior impacts the colligative properties of the solution, such as freezing point depression and boiling point elevation. As discussed earlier, in both phenomena, the non-ionic nature of urea means it affects these properties differently when compared to ionic solutes.Because urea molecules do not break into ions, the van 't Hoff factor, \(i\), remains equal to 1. Understanding these interactions and properties improves comprehension of broader concepts in chemistry, such as solubility and molecular interactions.