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The solubility of \(\mathrm{CO}_{2}\) in water at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) is \(0.034 \mathrm{~mol} / \mathrm{L}\). What is its solubility under atmospheric conditions? (The partial pressure of \(\mathrm{CO}_{2}\) in air is 0.0003 atm.) Assume that \(\mathrm{CO}_{2}\) obeys Henry's law.

Short Answer

Expert verified
The solubility is 0.0000102 mol/L.

Step by step solution

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01

Understanding Henry's Law

Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically, it is expressed as:\[ S = k_H \cdot P \]where \( S \) is the solubility of the gas (in mol/L), \( k_H \) is Henry's law constant (in mol/(L·atm)), and \( P \) is the partial pressure of the gas (in atm).
02

Calculate Henry's Constant

We are given that the solubility of \( CO_2 \) is 0.034 mol/L at a partial pressure of 1 atm. We can use this information to calculate Henry's law constant:\[ k_H = \frac{S}{P} = \frac{0.034 \, ext{mol/L}}{1 \, ext{atm}} = 0.034 \, ext{mol/(L·atm)} \]
03

Determine Solubility at New Conditions

Now, we need to find the solubility under the new partial pressure of 0.0003 atm. Using Henry's Law:\[ S = k_H \cdot P = 0.034 \, ext{mol/(L·atm)} \times 0.0003 \, ext{atm} \]
04

Calculate and Interpret the Result

Calculate the solubility:\[ S = 0.034 \, ext{mol/(L·atm)} \times 0.0003 \, ext{atm} = 0.0000102 \, ext{mol/L} \]Thus, the solubility of \( CO_2 \) under atmospheric conditions is \( 0.0000102 \, ext{mol/L} \).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Solubility
Gas solubility refers to how much of a gas can dissolve in a liquid. Imagine you are trying to mix sugar in your tea; similarly, gases can mix or dissolve in water or other liquids. This property depends on several factors such as temperature, pressure, and the nature of the gas and liquid.

When we talk about solubility in chemistry, we usually express it in terms of molarity, which is the number of moles of solute (in this case, a gas) per liter of solution. Understanding gas solubility is important because it affects many natural processes and industrial applications such as carbonated drinks, scuba diving, and the behavior of greenhouse gases in the atmosphere.
Partial Pressure
Partial pressure is the pressure that a gas in a mixture would exert if it were the only gas present. In a jug filled with different gases, each gas contributes to the total pressure. The partial pressure depends on the number of gas molecules and their kinetic energy.

In our exercise, we are calculating the solubility of carbon dioxide ( CO_2 ) under different atmospheric conditions. Carbon dioxide is one of many gases in the air we breathe. By knowing the partial pressure of CO_2 , we can apply principles like Henry's Law to determine how much of it will dissolve in water under those conditions.
CO2 Solubility
The solubility of CO_2 in water is a specific example of gas solubility. CO_2 is a common gas that we often encounter in carbonated beverages. When exposed to water, some of it will dissolve, creating carbonic acid which gives fizzy drinks their characteristic tangy taste.

The solubility is influenced by factors like temperature and the partial pressure of CO_2 above the liquid. As the partial pressure increases, CO_2 solubility in water also increases, following Henry's Law. This interaction is critical in understanding how climate change affects ocean acidity due to increased atmospheric CO_2 levels.
Chemical Equilibrium
Chemical equilibrium occurs when the rate of the forward reaction equals the rate of the backward reaction, creating a balanced state in a chemical reaction. In the context of CO_2 dissolution, this means the rate at which CO_2 molecules enter the water is equal to the rate at which they escape back into the air.

This balance ensures a steady solubility of CO_2 in a given condition, but it can be disturbed by changes in temperature or pressure. Understanding chemical equilibrium helps us grasp why, in the case of changes to atmospheric CO_2 levels, the ocean's chemistry may adjust differently over time.

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Most popular questions from this chapter

Arrange the following compounds in order of increasing solubility in water: \(\mathrm{O}_{2}, \mathrm{LiCl}, \mathrm{Br}_{2},\) methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\).

Acetic acid is a weak acid that ionizes in solution as follows: $$ \mathrm{CH}_{3} \mathrm{COOH}(a q) \rightleftarrows \mathrm{CH}_{3} \mathrm{COO}^{-}(a q)+\mathrm{H}^{+}(a q) $$ If the freezing point of a \(0.106 \mathrm{~m} \mathrm{CH}_{3} \mathrm{COOH}\) solution is \(-0.203^{\circ} \mathrm{C}\), calculate the percent of the acid that has undergone ionization.

A solution of \(6.85 \mathrm{~g}\) of a carbohydrate in \(100.0 \mathrm{~g}\) of water has a density of \(1.024 \mathrm{~g} / \mathrm{mL}\) and an osmotic pressure of 4.61 atm at \(20.0^{\circ} \mathrm{C}\). Calculate the molar mass of the carbohydrate.

Pheromones are compounds secreted by the females of many insect species to attract males. One of these compounds contains 80.78 percent \(\mathrm{C}, 13.56\) percent \(\mathrm{H},\) and 5.66 percent \(\mathrm{O}\). A solution of \(1.00 \mathrm{~g}\) of this pheromone in \(8.50 \mathrm{~g}\) of benzene freezes at \(3.37^{\circ} \mathrm{C}\). What are the molecular formula and molar mass of the compound? (The normal freezing point of pure benzene is \(\left.5.50^{\circ} \mathrm{C} .\right)\)

The solubility of \(\mathrm{N}_{2}\) in blood at \(37^{\circ} \mathrm{C}\) and at a partial pressure of 0.80 atm is \(5.6 \times 10^{-4} \mathrm{~mol} / \mathrm{L}\). A deep-sea diver breathes compressed air with the partial pressure of \(\mathrm{N}_{2}\) equal to \(4.0 \mathrm{~atm}\). Assume that the total volume of blood in the body is \(5.0 \mathrm{~L}\). Calculate the amount of \(\mathrm{N}_{2}\) gas released (in liters at \(37^{\circ} \mathrm{C}\) and \(\left.1 \mathrm{~atm}\right)\) when the diver returns to the surface of the water, where the partial pressure of \(\mathrm{N}_{2}\) is \(0.80 \mathrm{~atm}\).

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