Chapter 12: Problem 30
State whether each combination of elements would be expected to produce a semiconductor: (a) Ga and \(\mathrm{Sb},(\mathrm{b}) \mathrm{As}\) and \(\mathrm{N},(\mathrm{c}) \mathrm{B}\) and \(\mathrm{P}\) (d) \(\mathrm{Zn}\) and \(\mathrm{Sb}\), (e) \(\mathrm{Cd}\) and \(\mathrm{S}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Element Groups
Understanding which group an element belongs to helps in predicting its chemical behavior and potential to form semiconductors. These groups are not only a guide for semiconductor formation but also relate directly to the element's ability to conduct electricity under certain conditions.
III-V Semiconductors
The combination of group III elements, which have three valence electrons, with group V elements, which have five valence electrons, results in a perfect balance needed for semiconductor behavior. This property makes III-V semiconductors highly effective for applications like LEDs and high-frequency transistors.
II-VI Semiconductors
Similar to III-V semiconductors, the combination results in an ideal electronic structure that allows for electron movement, a requirement for semiconductors. These combinations are particularly useful in applications where wide bandgap materials are needed, allowing them to operate in high-temperature or high-power environments.
Periodic Table Groups
For semiconductors, understanding these groups is essential. Elements from group III, like boron and gallium, have three valence electrons, while those from group V, such as nitrogen and phosphorus, have five. These cross-group interactions provide the foundation for forming compounds with semiconducting properties.
n-type and p-type Materials
- n-type: Created by adding group V elements to a semiconductor, increasing free electrons.
- p-type: Formed by adding group III elements, creating 'holes' or positive charge carriers.