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Why are metals good conductors of heat and electricity? Why does the ability of a metal to conduct electricity decrease with increasing temperature?

Short Answer

Expert verified
Metals conduct well due to free electrons. Higher temperatures increase resistance, reducing conductivity.

Step by step solution

01

Understanding Metal Conductivity

Metals are good conductors of heat and electricity due to the presence of free electrons that can move easily throughout the metal lattice. These electrons act as charge carriers, facilitating the transfer of electric current and heat energy.
02

Relationship Between Conductivity and Temperature

As temperature increases, the metal atoms vibrate more intensely, which can scatter and impede the free electrons. This scattering reduces the mean free path of electrons, leading to an increase in resistance.
03

Explaining Temperature Effects

Since conductivity is inversely related to resistance, as resistance increases with temperature due to more intense atomic vibrations, the ability of the metal to conduct electricity decreases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metal Conductivity
Metals are renowned for their excellent conductivity of both heat and electricity, primarily due to the presence of free electrons within their structure. In metals, electrons are not tightly bound to individual atoms. Instead, they form a "sea of electrons" that can flow relatively freely throughout the metal lattice structure. This freedom allows these electrons to serve as efficient carriers of charge when an electrical potential is applied, hence facilitating electrical conductivity.
Moreover, the same free electrons, due to their mobility, also transfer thermal energy rapidly across the metal. This makes metals excellent conductors of heat. Here’s a quick overview of reasons why metals have high conductivity:
  • Presence of free electrons that can move through the metal lattice.
  • Low resistance to the flow of these electrons.
  • Ability of electrons to transfer energy quickly.
In summary, it's the presence of delocalized electrons in metals that enables them to conduct both heat and electricity so effectively.
Heat Transfer in Metals
The process of heat transfer in metals, known as thermal conductivity, is closely linked to the behavior of electrons in the metal. When one part of a metal is heated, the electrons in that area gain kinetic energy. Thanks to their freedom, these electrons quickly spread the gained energy to adjacent parts of the metal, dispersing the thermal energy throughout.
Unlike in insulators, where heat transfer occurs primarily through lattice vibrations known as phonons, in metals the electrons take charge (quite literally) in this heat exchange process. As such, metals are able to conduct heat much faster and more efficiently than non-metals. A few characteristics outline this process:
  • Free electrons gain energy more readily compared to atoms.
  • Electrons transfer this energy quickly throughout the metal.
  • Heat spreads uniformly through the metallic structure.
So, the role of freely moving electrons is crucial in the efficient heat conduction observed in metals.
Temperature Effect on Conductivity
Temperature has a significant impact on a metal's ability to conduct electricity, primarily due to how it affects the behavior of electrons and atoms. As the temperature of a metal increases, the atoms within the metal vibrate with greater intensity. These vibrations can interfere with the movement of free electrons, causing more frequent collisions.
With more frequent collisions, electrons are scattered, reducing their mean free path, or the average distance an electron travels between collisions. This scattering leads to an increase in electrical resistance, as electrons find it harder to move without disruption. Here's a breakdown of how temperature affects conductivity:
  • Increased atomic vibrations with rising temperature.
  • More frequent electron scattering due to these vibrations.
  • Increased resistance, which inversely affects conductivity.
Thus, as the resistance of a metal increases with temperature, its ability to conduct electricity decreases, making temperature a crucial factor in metal conductivity.

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Most popular questions from this chapter

The melting points of the oxides of the third-period elements are given in parentheses: \(\mathrm{Na}_{2} \mathrm{O}\left(1275^{\circ} \mathrm{C}\right)\) \(\mathrm{MgO}\left(2800^{\circ} \mathrm{C}\right), \mathrm{Al}_{2} \mathrm{O}_{3}\left(2045^{\circ} \mathrm{C}\right), \mathrm{SiO}_{2}\left(1610^{\circ} \mathrm{C}\right), \mathrm{P}_{4} \mathrm{O}_{10}\) \(\left(580^{\circ} \mathrm{C}\right), \mathrm{SO}_{3}\left(16.8^{\circ} \mathrm{C}\right), \mathrm{Cl}_{2} \mathrm{O}_{7}\left(-91.5^{\circ} \mathrm{C}\right) .\) Classify these solids in terms of crystal types.

A \(1.20-\mathrm{g}\) sample of water is injected into an evacuated \(5.00-\mathrm{L}\) flask at \(65^{\circ} \mathrm{C}\). What percentage of the water will be vapor when the system reaches equilibrium? Assume ideal behavior of water vapor and that the volume of liquid water is negligible. The vapor pressure of water at \(65^{\circ} \mathrm{C}\) is \(187.5 \mathrm{mmHg}\).

Select the substance in each pair that should have the higher boiling point. In each case identify the principal intermolecular forces involved and account briefly for your choice: (a) \(\mathrm{K}_{2} \mathrm{~S}\) or \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N},\) (b) \(\mathrm{Br}_{2}\) -or \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} .\)

A \(\mathrm{CO}_{2}\) fire extinguisher is located on the outside of a building in Massachusetts. During the winter months, one can hear a sloshing sound when the extinguisher is gently shaken. In the summertime there is often no sound when it is shaken. Explain. Assume that the extinguisher has no leaks and that it has not been used.

At what angle will \(\mathrm{X}\) rays of wavelength \(0.154 \mathrm{nm}\) be diffracted from a crystal if the distance (in \(\mathrm{pm}\) ) between layers in the crystal is \(188 \mathrm{pm}\) ? (Assume \(n=1\).)

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