Chapter 11: Problem 48
Vanadium crystallizes in a body-centered cubic lattice (the \(\mathrm{V}\) atoms occupy only the lattice points). How many \(\mathrm{V}\) atoms are present in a unit cell?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vanadium Crystallization
This arrangement is not only aesthetically intriguing but also plays a critical role in determining the material properties of vanadium, such as its strength and malleability. Crystallization is essential for materials science applications, including vanadium's use in alloys that strengthen steel.
Unit Cell Structure
Each corner atom touches neighboring cells as well, making the actual unit cell more interconnected than it might initially seem. Understanding the specifics of unit cell structures helps in predicting and explaining the macroscopic properties of the material, such as its density and elasticity.
Corner Atoms Contribution
To account for this, each corner atom is considered to contribute just one-eighth of an atom to the unit cell it is part of. Hence, with all eight corner atoms together in a BCC structure, their combined contribution boils down to one full atom ( \(8 \times \frac{1}{8} = 1\) atom) in that single cell. This calculation is crucial for determining the number of atoms truly present in the unit cell.
Center Atom Contribution
The concept becomes handy when trying to calculate the total number of atoms present in any arrangement. In the case of vanadium in a BCC lattice, the center atom adds one full atom outright, leading to a total of two atoms within the unit cell when combined with the corner atoms' contributions.