Chapter 11: Problem 104
\(\mathrm{X}\) rays of wavelength \(0.154 \mathrm{nm}\) are diffracted from a crystal at an angle of \(14.17^{\circ} .\) Assuming that \(n=1\), calculate the distance (in pm) between layers in the crystal.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bragg's Law
- \( n\lambda = 2d \sin \theta \)
- \( n \) represents the order of diffraction, usually an integer starting with 1.
- \( \lambda \) is the wavelength of the incoming X-ray beam.
- \( d \) stands for the distance between layers in a crystal.
- \( \theta \) is the angle at which the X-rays are diffracted.
Crystal Layer Spacing
Materials have unique, fixed arrangements of atoms in their structure, forming layers.
This layer distance influences the diffraction pattern when an X-ray hits the material.Given that X-ray diffraction aids in determining crystal structures, knowing how to calculate \( d \) helps identify materials. To find \( d \), rearrange Bragg's Law to:
- \( d = \frac{n\lambda}{2 \sin \theta} \)
Wavelength Conversion
In our example, the wavelength \( \lambda \) was given as 0.154 nm.To perform calculations, convert to other units:
- From nanometers to meters: Multiply by \( 10^{-9} \).
- From nanometers to picometers: Multiply by 1000, since 1 nm = 1000 pm.
Trigonometric Calculations
Here, we need \( \sin \theta \) for \( \theta = 14.17° \).The sine function is a ratio that helps determine the height of the opposite side of an angle in a right triangle over its hypotenuse:
- \( \sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} \)
- For 14.17°, \( \sin 14.17° \approx 0.245 \).
- \( d = \frac{n\lambda}{2 \sin \theta} \)