Chapter 11: Problem 104
\(\mathrm{X}\) rays of wavelength \(0.154 \mathrm{nm}\) are diffracted from a crystal at an angle of \(14.17^{\circ} .\) Assuming that \(n=1\), calculate the distance (in pm) between layers in the crystal.
Short Answer
Expert verified
The distance between layers in the crystal is approximately 314.29 pm.
Step by step solution
01
Understand the diffraction formula
For X-ray diffraction, the relevant formula is Bragg's Law: \( n\lambda = 2d \sin \theta \). Here, \( n \) is the order of diffraction, \( \lambda \) is the wavelength, \( d \) is the distance between crystal layers, and \( \theta \) is the angle of diffraction.
02
Convert units
First, convert the wavelength \( \lambda = 0.154 \text{ nm} \) into meters: \( 0.154 \text{ nm} = 0.154 \times 10^{-9} \text{ m} \). To find \( d \) in picometers (pm), remember that 1 nm = 1000 pm, so \( 0.154 \text{ nm} = 154 \text{ pm} \).
03
Plug values into Bragg's Law
We know \( n = 1 \), \( \lambda = 0.154 \text{ nm} = 154 \text{ pm} \), and \( \theta = 14.17^{\circ} \). Convert \( \theta \) to radians if necessary, then use the equation: \( d = \frac{n\lambda}{2 \sin \theta} \).
04
Calculate \( \sin \theta \)
Calculate \( \sin 14.17^{\circ} \): \( \sin 14.17^{\circ} \approx 0.245 \).
05
Solve for \( d \)
Substitute the values into the Bragg's Law rearranged formula to find \( d \):\[ d = \frac{1 \times 154}{2 \times 0.245} = \frac{154}{0.49} \approx 314.29 \text{ pm}.\]
06
Final Answer
The distance between layers in the crystal is approximately \( 314.29 \text{ pm} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bragg's Law
X-ray diffraction is described by a neat and elegant equation known as Bragg's Law. This formula is crucial for understanding how X-rays bounce off crystal layers. It is stated as:
- \( n\lambda = 2d \sin \theta \)
- \( n \) represents the order of diffraction, usually an integer starting with 1.
- \( \lambda \) is the wavelength of the incoming X-ray beam.
- \( d \) stands for the distance between layers in a crystal.
- \( \theta \) is the angle at which the X-rays are diffracted.
Crystal Layer Spacing
The distance between crystal layers, noted as \( d \), is crucial to understanding how materials interact with X-rays.
Materials have unique, fixed arrangements of atoms in their structure, forming layers.
This layer distance influences the diffraction pattern when an X-ray hits the material.Given that X-ray diffraction aids in determining crystal structures, knowing how to calculate \( d \) helps identify materials. To find \( d \), rearrange Bragg's Law to:
Materials have unique, fixed arrangements of atoms in their structure, forming layers.
This layer distance influences the diffraction pattern when an X-ray hits the material.Given that X-ray diffraction aids in determining crystal structures, knowing how to calculate \( d \) helps identify materials. To find \( d \), rearrange Bragg's Law to:
- \( d = \frac{n\lambda}{2 \sin \theta} \)
Wavelength Conversion
Understanding the wavelengths in X-ray diffraction is pivotal since they are usually measured in nanometers (nm), and calculations often require conversion.
In our example, the wavelength \( \lambda \) was given as 0.154 nm.To perform calculations, convert to other units:
In our example, the wavelength \( \lambda \) was given as 0.154 nm.To perform calculations, convert to other units:
- From nanometers to meters: Multiply by \( 10^{-9} \).
- From nanometers to picometers: Multiply by 1000, since 1 nm = 1000 pm.
Trigonometric Calculations
In diffraction problems, trigonometry plays an integral role because it involves angles and their sine values.
Here, we need \( \sin \theta \) for \( \theta = 14.17° \).The sine function is a ratio that helps determine the height of the opposite side of an angle in a right triangle over its hypotenuse:
Here, we need \( \sin \theta \) for \( \theta = 14.17° \).The sine function is a ratio that helps determine the height of the opposite side of an angle in a right triangle over its hypotenuse:
- \( \sin \theta = \frac{\text{Opposite}}{\text{Hypotenuse}} \)
- For 14.17°, \( \sin 14.17° \approx 0.245 \).
- \( d = \frac{n\lambda}{2 \sin \theta} \)