Chapter 10: Problem 85
At a certain temperature the speeds of six gaseous molecules in a container are \(2.0,2.2,2.6,2.7,3.3,\) and \(3.5 \mathrm{~m} / \mathrm{s}\). Calculate the root-mean-square speed and the average speed of the molecules. These two average values are close to each other, but the root-mean-square value is always the larger of the two. Why?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gaseous Molecules
Average Speed
- Calculate the sum of all individual speeds.
- Divide this sum by the total number of speeds.
Speed Calculation
For RMS speed, the process is slightly more complex.
- First, you square each individual speed to emphasize larger speeds.
- Then, you take the mean of these squared speeds by dividing by the number of molecules.
- Finally, take the square root of this mean to arrive at the RMS speed.
RMS and Average Speed Comparison
RMS speed often appears slightly larger than the average speed because the squaring process during calculation gives extra emphasis to faster molecules. This squaring step essentially magnifies the effect of higher outlier speeds, causing the RMS speed to weigh more on these larger values.
Thus, while the average speed provides a simple mean of all speeds, RMS speed offers a weighted perspective, skewed towards higher speed contributions. This characteristic of RMS speed makes it useful in contexts where greater insight into energetic dynamics is required, such as in thermal physics and kinetic theory of gases.