Chapter 10: Problem 45
At 741 torr and \(44^{\circ} \mathrm{C}, 7.10 \mathrm{~g}\) of a gas occupies a volume of \(5.40 \mathrm{~L}\). What is the molar mass of the gas?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
In the exercise provided, you calculated the molar mass by first finding the number of moles of the gas. The number of moles \( n \) was found using the Ideal Gas Law, which relates pressure, volume, and temperature to moles. The equation used is:
- \( n = \frac{PV}{RT} \)
Once you have \( n \), the molar mass \( M \) can be calculated by dividing the mass of the gas by the moles of the gas:
- \( M = \frac{\text{mass of the gas}}{n} \)
Gas Laws
This law essentially combines several other gas laws into one comprehensive formula: Boyle's Law, Charles's Law, and Avogadro's Law. Each of these describes the relationship between pairs of physical properties of a gas:
- Boyle's Law: Pressure and volume are inversely proportional at constant temperature.
- Charles's Law: Volume and temperature are directly proportional at constant pressure.
- Avogadro's Law: Volume is directly proportional to the number of moles of gas at constant temperature and pressure.
This is particularly useful in determining unknown characteristics of gases in experimental setups, like calculating the molar mass.
Unit Conversion
First, we needed to convert temperature from Celsius to Kelvin. This is necessary because Kelvin is the unit used in scientific calculations and the Ideal Gas Law. To convert Celsius to Kelvin, simply add 273.15 to the Celsius value:
- \( T(K) = T(°C) + 273.15 \)
- \( P(atm) = \frac{P(torr)}{760} \)
This is crucial for accurate calculations and helps prevent common errors that occur when different unit systems are mixed.