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Why is the density of a gas much lower than that of a liquid or solid under atmospheric conditions? What units are normally used to express the density of gases?

Short Answer

Expert verified
Gas density is lower due to molecule separation. Expressed in g/L.

Step by step solution

01

Understanding Density

Density is defined as mass per unit volume. It is generally represented by the formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]The density of gases, liquids, and solids varies due to variations in their molecular arrangements and interactions.
02

Molecular Arrangement of Gases vs. Liquids/Solids

Gases consist of molecules that are significantly separated from each other, with a lot of empty space in between, leading to lower mass in a given volume compared to liquids and solids where molecules are closely packed and interact strongly, hence creating high density.
03

Effect of Atmospheric Conditions

Under atmospheric conditions, gases expand to fill their containers, increasing the volume and thus decreasing their density. Liquids and solids have fixed volumes which results in higher densities.
04

Units for Gas Density

The density of gases is often expressed in units of grams per liter (g/L) in chemistry to account for the large volumes gases can occupy, unlike liquids and solids which are often expressed in grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Arrangement
In gases, the molecular arrangement is quite different compared to liquids and solids. Molecules in gases are far apart, with substantial space between them. This results in minimal interaction between the molecules, meaning they move freely and randomly. Such a loose arrangement contrasts sharply with the tightly packed molecules found in liquids and solids.
  • In solids, molecules are closely packed in an orderly manner, which results in limited movement and high density.
  • Liquids have molecules that are less tightly packed than solids, allowing for flow, but they still maintain a dense arrangement compared to gases.
  • Gas molecules, however, have vast amounts of space between them, leading to much lower densities.
Understanding this difference in molecular arrangement helps explain why gas density is generally low.
Atmospheric Conditions
Atmospheric conditions play a significant role in determining the density of gases. At standard atmospheric pressure and temperature, gases are capable of expanding to fill any container. This expansion significantly increases the volume they occupy.
As the volume of a gas increases, its density decreases because density is inversely proportional to volume when mass remains constant.
  • Gases adapt to the container's shape, demonstrating their variable volume but often resulting in a low-density value.
  • Conversely, liquids and solids have fixed shapes and volumes, so their densities remain higher under the same conditions.
Hence, gases are less dense because they expand and occupy more space under atmospheric conditions.
Units of Density
Density is commonly expressed in various units depending on the state of matter. For gases, the density is often stated in grams per liter (g/L). This unit is used because gases typically occupy large volumes at standard temperature and pressure.
  • This contrasts with the density of liquids and solids, typically given in grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).
  • Gases like oxygen or nitrogen, which are abundant in the atmosphere, have densities around 1.4 g/L and 1.25 g/L, respectively.
These units effectively accommodate the expansive nature of gases, providing a clear understanding of their relatively low density.
Mass and Volume Relationship
The mass and volume relationship forms the foundation of understanding density. Density is calculated using the formula: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
This equation reveals thatthe density of a substance depends on how much mass exists in a given volume. For gases, with their large volume and often smaller mass in comparison to liquids and solids, the resulting density number is low.
  • A small increase in the volume of a gas (without adding more mass) results in a decrease in density.
  • In contrast, solids and liquids generally maintain constant volumes, so their densities are higher given the same mass conditions.
Therefore, understanding the mass and volume relationship is vital in explaining why gases are far less dense.

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Most popular questions from this chapter

A mixture of helium and neon gases is collected over water at \(28.0^{\circ} \mathrm{C}\) and \(745 \mathrm{mmHg}\). If the partial pressure of helium is \(368 \mathrm{mmHg}\), what is the partial pressure of neon? (Vapor pressure of water at \(28^{\circ} \mathrm{C}=28.3 \mathrm{mmHg} .\) )

A stockroom supervisor measured the contents of a 25.0-gal drum partially filled with acetone on a day when the temperature was \(18.0^{\circ} \mathrm{C}\) and atmospheric pressure was \(750 \mathrm{mmHg}\), and found that 15.4 gal of the solvent remained. After tightly sealing the drum, an assistant dropped the drum while carrying it upstairs to the organic laboratory. The drum was dented, and its internal volume was decreased to 20.4 gal. What is the total pressure inside the drum after the accident? The vapor pressure of acetone at \(18.0^{\circ} \mathrm{C}\) is \(400 \mathrm{mmHg}\). (Hint: At the time the drum was sealed, the pressure inside the drum, which is equal to the sum of the pressures of air and acetone, was equal to the atmospheric pressure.)

A certain hydrate has the formula \(\mathrm{MgSO}_{4} \cdot x \mathrm{H}_{2} \mathrm{O} .\) A quantity of \(54.2 \mathrm{~g}\) of the compound is heated in an oven to drive off the water. If the steam generated exerts a pressure of 24.8 atm in a 2.00-L container at \(120^{\circ} \mathrm{C}\), calculate \(x\)

A mixture of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) and \(\mathrm{MgCO}_{3}\) of mass \(7.63 \mathrm{~g}\) is combined with an excess of hydrochloric acid. The \(\mathrm{CO}_{2}\) gas generated occupies a volume of \(1.67 \mathrm{~L}\) at 1.24 atm and \(26^{\circ} \mathrm{C}\). From these data, calculate the percent composition by mass of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) in the mixture.

Ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) burns in air: $$ \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) $$ Balance the equation and determine the volume of air in liters at \(45.0^{\circ} \mathrm{C}\) and \(793 \mathrm{mmHg}\) required to burn \(185 \mathrm{~g}\) of ethanol. Assume that air is 21.0 percent \(\mathrm{O}_{2}\) by volume.

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