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A 28.4-L volume of methane gas is heated from \(35^{\circ} \mathrm{C}\) to \(72^{\circ} \mathrm{C}\) at constant pressure. What is the final volume of the gas?

Short Answer

Expert verified
The final volume of the gas is approximately 31.84 L.

Step by step solution

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01

Identify the Known Variables

First, we need to identify the known variables and the formula to use. We have the initial volume \( V_1 = 28.4 \text{ L} \), the initial temperature \( T_1 = 35^{\circ} \text{C} = 308.15 \text{ K} \) after converting to Kelvin, and the final temperature \( T_2 = 72^{\circ} \text{C} = 345.15 \text{ K} \).
02

Apply Charles's Law

Charles's Law states that \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \), where \( V_2 \) is the final volume we need to find. Rearrange this equation to solve for \( V_2 \): \( V_2 = \frac{V_1 T_2}{T_1} \).
03

Substitute the Known Values

Now substitute the known values into the equation: \( V_2 = \frac{28.4 \text{ L} \times 345.15 \text{ K}}{308.15 \text{ K}} \).
04

Calculate the Final Volume

Perform the calculation: \( V_2 = \frac{28.4 \times 345.15}{308.15} \approx 31.84 \text{ L} \). So, the final volume of the gas is approximately 31.84 L.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Gas laws describe how gases behave under various conditions of pressure, volume, and temperature. A primary gas law relevant here is Charles's Law. Charles's Law shows how the volume of a gas changes in relation to its temperature when the pressure is constant.

Specifically, it states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming pressure remains constant. This means if you increase the temperature of a gas, its volume will also increase and vice versa, as long as the pressure doesn’t change.
  • The mathematical representation is: \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \), where \( V \) is volume and \( T \) is temperature.
  • This relationship is crucial for understanding how gases expand and contract in different conditions.
Temperature Conversions
In gas law calculations, temperatures must be in Kelvin. Kelvin is an absolute temperature scale and necessary for calculations because it starts at absolute zero.

To convert Celsius to Kelvin, simply add 273.15 to the Celsius temperature. For example, \( 35^{\circ} \text{C} \) becomes \( 308.15 \text{ K} \), as seen in the original exercise.
  • Always convert to Kelvin before using gas law formulas like Charles's Law.
  • Remember, no negative numbers occur in Kelvin, which simplifies calculations and maintains consistency with the laws of thermodynamics.
Volume Calculations
To find the final volume of a gas after a temperature change, apply Charles's Law once you've converted all temperatures to Kelvin. This involves substituting known values into the rearranged formula \( V_2 = \frac{V_1 T_2}{T_1} \).

Volume calculations like this require careful handling of units and temperatures to ensure accuracy:
  • With an initial volume \( V_1 \) of 28.4 L, initial temperature \( T_1 \) of 308.15 K, and final temperature \( T_2 \) of 345.15 K, plug into the formula to isolate \( V_2 \).
  • It's important to follow through with each step completely to avoid errors and attain the correct final volume.
Ideal Gas Behavior
Ideal gas behavior assumes gases consist of small particles in random, swift motion and that they exhibit no intermolecular forces. In real-world contexts, gases approximate ideal behavior at high temperatures and low pressures.

For the purposes of calculations like with Charles's Law, assuming ideal gas behavior means the gas will follow the gas laws accurately without deviation. This assumption simplifies equations and makes calculations more straightforward.
  • Ideal behavior implies gas particles do not attract or repel each other.
  • Most gases, under normal conditions, behave ideally, thus making this assumption valid in many practical scenarios.

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Most popular questions from this chapter

Dry ice is solid carbon dioxide. A \(0.050-\mathrm{g}\) sample of dry ice is placed in an evacuated 4.6-L vessel at \(30^{\circ} \mathrm{C}\). Calculate the pressure inside the vessel after all the dry ice has been converted to \(\mathrm{CO}_{2}\) gas.

A piece of sodium metal reacts completely with water as follows: $$ 2 \mathrm{Na}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaOH}(a q)+\mathrm{H}_{2}(g) $$ The hydrogen gas generated is collected over water at \(25.0^{\circ} \mathrm{C}\). The volume of the gas is \(246 \mathrm{~mL}\) measured at 1.00 atm. Calculate the number of grams of sodium used in the reaction. (Vapor pressure of water at \(25^{\circ} \mathrm{C}=0.0313\) atm. \()\)

Discuss the following phenomena in terms of the gas laws: (a) the pressure increase in an automobile tire on a hot day, (b) the "popping" of a paper bag, (c) the expansion of a weather balloon as it rises in the air, (d) the loud noise heard when a lightbulb shatters.

A mixture of gases contains \(0.31 \mathrm{~mol} \mathrm{CH}_{4}, 0.25 \mathrm{~mol}\) \(\mathrm{C}_{2} \mathrm{H}_{6}\), and \(0.29 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}\). The total pressure is \(1.50 \mathrm{~atm} .\) Calculate the partial pressures of the gases.

A stockroom supervisor measured the contents of a 25.0-gal drum partially filled with acetone on a day when the temperature was \(18.0^{\circ} \mathrm{C}\) and atmospheric pressure was \(750 \mathrm{mmHg}\), and found that 15.4 gal of the solvent remained. After tightly sealing the drum, an assistant dropped the drum while carrying it upstairs to the organic laboratory. The drum was dented, and its internal volume was decreased to 20.4 gal. What is the total pressure inside the drum after the accident? The vapor pressure of acetone at \(18.0^{\circ} \mathrm{C}\) is \(400 \mathrm{mmHg}\). (Hint: At the time the drum was sealed, the pressure inside the drum, which is equal to the sum of the pressures of air and acetone, was equal to the atmospheric pressure.)

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