Chapter 10: Problem 23
The volume of a gas is \(7.15 \mathrm{~L},\) measured at \(1.00 \mathrm{~atm} .\) What is the pressure of the gas in \(\mathrm{mmHg}\) if the volume is changed to \(9.25 \mathrm{~L}\) ? (The temperature remains constant.)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gas Laws
These laws are derived from the ideal gas law equation: \[ PV = nRT \] where
- \(P\) is the pressure of the gas,
- \(V\) is the volume of the gas,
- \(n\) is the number of moles,
- \(R\) is the ideal gas constant, and
- \(T\) is the temperature in Kelvin.
Pressure-Volume Relationship
- \(P_1\) and \(P_2\) refer to the initial and final pressures, respectively, and
- \(V_1\) and \(V_2\) refer to the initial and final volumes.
Pressure Conversion
For example, the conversion factor between atmospheres and millimeters of mercury is based on the fact that:
- 1 atm = 760 mmHg
Constant Temperature Process
In the context of the pressure-volume relationship, maintaining a constant temperature means that any change in the volume will directly affect the pressure and vice versa. Since the temperature does not change, the energy distribution among gas molecules remains steady, and only their spatial distribution changes.
When employing Boyle's Law in calculations, the assumption of a constant temperature allows us to focus exclusively on solving for unknown pressures or volumes, confidently knowing temperature does not influence the outcome.